Key Concepts
- The inverse of a relation.
- An equation of an inverse relation.
- The domain and range of an inverse function and restrict the domain of a function.
- An equation of an inverse function.
- Verify inverse functions by using composition.
- Use inverse function to rewrite a formula.
Domain and Range
Domain
The set of all possible values which qualify as inputs to a function or can also be defined as the entire set of values possible for independent variables.
Range
The set of all the output of a function is known as the range of the function or the entire set of all values possible as outcomes of the dependent variable.
Consider the following set of ordered pairs:
{(1, 2), (2, 4), (3, 6), (4, 8), (5, 10)}
The domain is {1, 2, 3, 4, 5}.
The range is {2, 4, 6, 8, 10}.
Question 1: Find the domain and range of the functions given below:
- √3x+1
- 5x−3
- 2|x−7|
Solution 1a:
Given function √3x+1
3x+1≥0
x≥−1/3
So, the domain of the function √3x+1 is x≥−1/3.
And the range of the function √3x+1 is y≥0.
Solution 1b:
Given function 5x−3
The domain of the function 5x−3 is the set of all real numbers.
The range of the function 5x−3 is the set of all real numbers.
Solution 1c:
Given function 2|x−7|
So, the domain of the function 2|x−7| is the set of all real numbers.
And the range of the function 2|x−7| is y≥0.
Question 2: Fill the table as given below:
Solution 2:
When x=0 , then y = a = 8−3×0 =8
When y=2 , then 2 = 8−3b
3b = 8−2
b = 2
When x = 3 , then y = c = 8−3×3 = −1
Inverse of a relation
Inverse relation
An inverse relation is formed when the roles of the independent and dependent variables are reversed.
Consider a tabular column:
Here x is the independent variable and y is the dependent variable.
Inverse function
If an inverse relation of a function, f , is itself a function, it is called the inverse function of f.
An inverse function is written as f−1(x).
Consider a tabular column:
Here, the domain of f do not have the same image, then the inverse of f is a function.
An equation of an inverse relation
Equation of inverse relation can be represented in two ways:
- Algebraically
- Graphically
Representing equation of inverse relation algebraically:
Consider fx = x2
y = x2
x = y2 (Switch the roles of x and y)
y = ±√x (Solve for y)
The inverse of f can be represented algebraically by the equation y = ±√x.
Representing equation of inverse relation graphically
The graphs of y = x2 and y = ±√x
The graph of the inverse of f is the reflection of the graph of y = x2 across the line y = x.
Restrict a domain to produce an inverse function
Consider the function y = x2
For a relation to be a function, no two values of x should have the same value as y.
If a function has two x−values for the same y−value, its inverse will not be a function.
Restrict the domain of a function such that its inverse also becomes a function.
The inverse relation of f(x) = x2 is y = ±√x.
If the domain of f(x) = x2 is restricted to x≥0, then the inverse is the function defined as f−1(x)=√x.
Equation of an inverse function
Consider a function √𝒇𝒙=𝒙−𝟐
.
From the graph, there is no horizontal line that intersects the graph at more than one point.
When the graph is reflected over the line 𝒚=𝒙 to produce an inverse, there will be no vertical line that will intersect the graph at more than one point.
So, the inverse relation will be a function.
Let, y = x−2
Switch the roles of x and y and then solve for y.
x=√y−2 ⇒ x2=y−2
x2+2=y
So, the inverse of f(x)=√x−2 is a function,
f−1(x)=x2+2, x≥0.
Here the graph of f and f−1 are both functions and are reflections over the line y = x.
Use composition to verify inverse functions
The functions f(x) and g(x) are said to be inverse functions of each other if
(𝒇o𝒈)(𝒙) =𝒙 and
(gof)(x) = x
Verification:
Let f(x) be a function and its inverse gx=f−1(x) be the inverse function of f(x).
Consider, (fog)(x)=f(g(x))
= f(f−1(x))
= x
Now consider,
(gof)(x)=g(f(x))
=f−1( f(x))
=x
(fog)(x)=x & (gof)(x)=x
So, the functions f(x) and g(x) are said to be inverse functions.
Example:
Use composition to determine whether f(x)=∛x−1 and g(x)=x3+1 are inverse functions.
Solution:
Given
f(x)=∛x−1 and g(x)=x3+1
To be inverse functions,
(fog)(x)=x and (gof)(x)=x.
Rewrite Formula
Example:
A sculpture artist is making an ice sculpture of Earth for a display. He created a mould that can hold 4.5 L of ice. What will be the radius of the ice sculpture if he fills the mould all the way?
Solution:
The volume of the sphere, V = 4/3 πr3
Rewrite the formula to find the length of the radius.
4/3 πr3 = v
πr3 = 3/4 v
r3 = 3/4π v
r = ∛3/4𝜋 V
One liter is equivalent to 1000cm3.
So, 4.5L is equivalent to 4500cm3.
r = ∛3/4𝜋 V
≈10.2 cm.
The ice sculpture mould will have a radius of about 10 cm.
So, in the original equation the value of V depends on the value of r.
Exercise
- Identify the inverse relation. Is it a function?
- Find an equation of the inverse function of fx= 2-∛x+1.
- Use composition to determine whether fx=3x+12, gx=1/3x-4 are inverse functions.
Concept Summary
What we have learned
- Represent the inverse of a relation.
- Find an equation of an inverse relation.
- Determine the domain and range of an inverse function and restrict the domain of a function.
- Find an equation of an inverse function.
- Use composition to verify inverse functions.
- Use inverse function to rewrite a formula.
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