Key Concepts
- What is an angle.
- Solve problems involving adjacent and vertical angles.
- Solve problems involving complementary and supplementary angles.
- Find the measure of an unknown angle.
8.4 Solve problems using angle relationship
Angle:
The measure of rotation of a ray from its initial position to terminal position about a fixed point ‘O’ is defined as an angle.
(OR)
In geometry, an angle can be defined as the figure formed by two rays meeting at a commonend point. The angle is represented by the symbol “
∠
”. The angle above is written as
∠∠AOB.
Parts of an angle:
Arms: The two rays that are joining to form an angle are called arms of an angle. Here, OA and OB are arms of
∠
AOB.
Vertex: The common endpoint at which the two rays meet to form an angle is called the vertex. Here, point O is the vertex of
∠AOB.
Examples of angles:
- Angle formed in a pair of scissors
- Angle formed between the spokes of a wheel
- Angle formed between index and thumb finger
Types of angles:
Angles can be classified based on their measurements as:
- Acute angle
- Right angle
- Obtuse angle
- Straight angle
- Reflex angle
- Complete angle
Adjacent angles:
Two angles are said to be adjacent angles if they share a common vertex and side. Adjacent angles can be a complementary angle or a supplementary angle when they share the common vertex and side.
Here, we observe that
∠AOB and∠BOC have a common arm, i.e., OB and a common vertex O.
Therefore,∠AOB and∠BOC can be called adjacent angles.
Vertical angles:
When a pair of lines intersect each other at a common point, then four angles are formed. Two non-adjacent angles that are opposite and equal are called vertical angles or vertically opposite angles.
Example:
Complementary angles:
Two angles are said to be complementary if they add up to 90⁰. Complementary angles can be adjacent or non-adjacent angles.
Supplementary angles:
Two angles are said to be supplementary if they add up to 180⁰. Supplementary angles can be adjacent or non-adjacent angles. They form a straight line if they are adjacent angles.
8.4.1 Solve problems involving adjacent and vertical angles
Example 1: From the figure given below, find the value of ‘x’ and the measure of
∠AOC and∠BOD.
Solution: We know that vertical angles have equal measures.
∠AOC and∠BOD are the vertical angles.
Step 1: Since
∠AOC and∠BOD is equal, we write m
∠AOC = m
∠BOD 2x + 96 = 5x – 9
2x + 96 + 9 = 5x – 9 + 9 (∵Add 9 on both the sides)
2x + 105 = 5x
2x + 105 – 2x = 5x – 2x (∵Subtract 2x from both sides)
105 = 3x
105/3=3×3 (∵Divide by 3 on both sides of the equation)
35 = x
Therefore, value of x = 35.
m ∠AOC = 2x + 96 m ∠BOD = 5x – 9
= 2(35) + 96 = 5(35) – 9
= 70 + 96 = 175 – 9
= 166 = 166
Example 2:
∠MNQ and ∠PNR are vertical angles. Find the value of ‘x’.
Solution: We know that vertical angles have equal measures.
∠MNQ and∠PNR are the vertical angles.
Step 1: Since
∠MNQ and ∠PNR is equal, we write m
∠MNQ = m ∠PNR
3x – 6 = 114
3x – 6 + 6 = 114 + 6 (∵Add 9 on both the sides)
3x = 120
3x / 3 = 120 / 3 (∵Divide by 3 on both sides of the equation)
x = 40
Therefore, value of x = 40.
m ∠MNQ = 3x – 6
= 3(40) – 6
= 120 – 6
= 114
8.4.2 Solve problems involving complementary and supplementary angles
Example 1: Determine the value of ‘x’ in the given figure.
Solution:
We know that sum of two adjacent angles is complementary by observing the figure.
Step 1: m∠AOB + m∠BOC = 90⁰
x + 62 = 90⁰
x = 90⁰ – 62
x = 28⁰
Example 2: Determine the value of ‘x’ if the following two angles are supplementary.
Solution:
We know that sum of two angles is supplementary.
Step 1:
x / 2+ x /3 = 180
3 × x+2 ×x / 6 = 180
3x+2x / 6= 180
5x / 6 = 180
5x X 6 / 6 = 180 × 6 (∵Multiply by 6 on both the sides)
5x = 1080 (∵Divide by 5 on both the sides)
5x / 5 =10805
x = 216⁰
8.4.3 Find the measure of an unknown angle
Example 1: If three lines AB, CD and EF intersect each other at a common point ‘O’ such that AB is perpendicular to CD, determine the value of y and
∠AOE.
Solution: We know that AB is perpendicular to CD. So, m
∠AOC = 90⁰.
Step 1: Use vertical angles to find the value of ‘y’.
m∠COE = m∠DOF
5y + 16 = 3y + 20
5y + 16 – 3y = 3y + 20 – 3y (∵Subtract 3y on both the sides)
2y + 16 = 20
2y + 16 – 16 = 20 –16 (∵Subtract 16 on both the sides)
2y = 4
2y / 2 = 4 / 2 (∵Divide by 2 on both the sides)
y = 2
∠COE = 5y + 16
= 5(2) + 16
= 10 + 16
∠COE = 26
Step 2: We observe that
∠AOE and∠COE are complementary. Since AB and CD are perpendicular to each other.
∠AOC = 90⁰
∠AOE +∠COE = 90⁰
∠AOE + 26⁰ = 90⁰
∠AOE = 90⁰ – 26⁰
∠AOE = 64⁰
Exercise:
- How are angles formed by intersecting lines related?
- Can we say that vertical angles are also adjacent angles? Explain.
- List two pairs of adjacent angles and vertical angles from the figure given below.
- In the given figure, AB, CD and EF intersect at O. Find the values of x, y and z if it is being given that x:y:z =2:3:5
- Two angles are equal and complementary to each other. Determine the measure of the two angles.
- Determine the value of ‘x’ in the figure given below.
- Determine the complement angle of 35⁰.
- Two angles are equal and supplementary to each other. Determine the measure of the two angles.
- Determine the value of a from the figure given below.
- Determine the supplement angle of 123⁰.
What have we learned?
- What an angle is?
- Solving problems involving adjacent and vertical angles.
- Solving problems involving complementary and supplementary angles.
- Determining the measure of an unknown angle
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