Key Concepts
- Use congruent triangles
Introduction:
Use congruent triangles
Example 1: In the given figure, AB = BC and AD = CD. Show that BD bisects AC at right angles.
Solution:
From the given figure, ∆ABD ≅ ∆CBD
Given: AB = BC and AD = CD
To prove: ∠BEA = ∠BEC = 90° and AE = EC.
Proof:
AB = BC (Given)
AD = CD (Given)
BD = BD (Common sides)
Therefore, ∆ABD ≅ ∆CBD (By SSS congruency)
∠ABD = ∠CBD (Corresponding angles)
Now, from ∆ABE and ∆CBE,
AB = BC (Given)
∠ABD = ∠CBD (Corresponding angles)
BE = BE (Common sides)
Therefore, ∆ABE≅ ∆CBE (By SAS congruency)
∠BEA = ∠BEC (Corresponding angles)
And ∠BEA +∠BEC = 180° (Linear pair)
2∠BEA = 180° (∠BEA = ∠BEC)
∠BEA =
180°2180°2
= 90° = ∠BEC
AE = EC (Corresponding sides)
Hence, BD
⊥⊥
AC.
Example 2: In a Δ ABC, if AB = AC and ∠ B = 70°, find ∠ A.
Solution:
Given: AB = AC and ∠B = 70°
∠ B = ∠ C [Angles opposite to equal sides are equal]
Therefore, ∠ B = ∠ C = 70°
Sum of angles in a triangle = 180°
∠ A + ∠ B + ∠ C = 180°
∠ A + 70° + 70° = 180°
∠ A = 180° – 140°
∠ A = 40°.
Example 3: In the given figure, PQ = PS and QPR = SPR. Prove that PQR PSR, and use the SAS congruence postulate.
Solution:
In QPR and PSR,
PQ = PS (Given)
∠QPR = ∠SPR (Given)
PR = PR (Common sides)
Therefore, ∆PQR ≅ ∆PSR (By SAS congruence).
Example 4: Identify the congruent triangle in the given figure.
Solution:
In ∆LMN,
65° + 45° + ∠L = 180°
110° + ∠L = 180°
∠L = 180° – 110°
Therefore, ∠L = 70°
Now in ∆XYZ and ∆LMN
∠X = ∠L (Given)
XY = LM (Given)
XZ = NL (Given)
Therefore, ∆XYZ ≅ ∆LMN by SAS congruence postulate.
Example 5:
Write a 2-column proof for the given figure.
Given: BD is an angle bisector of CDA, C A
To prove: △CBD ≅ ∠ABD
Solution:
How to prove construction:
The following steps explain the construction of congruent triangles:
Step 1:
To copy A, draw a segment starting at point D. Draw an arc with the center A. Using the same radius, draw an arc with center D. Label points B, C, and E.
Step 2:
Draw an arc with radius BC and center E. Label the intersection F.
Step 3:
Draw
DF−→−DF→
.
Example 6:
Write a proof to verify that the construction for copying an angle is valid.
Solution:
Add
BC−BC-
and
EF−EF- to the diagram. In the construction,
AB−AB-,
DE−DE-,
AC−AC-, and
DF−DF- are determined by the same compass. So, the required construction is
BC−BC- and
EF−EF-.
Given:
AB−AB-
≅
DE−DE-,
AC−AC- ≅
DF−DF-,
BC−BC- ≅
EF−EF-.
To prove:
∠∠
D ≅
∠∠A
Plan for Proof:
Show that △CAB ≅ △FDE, so we can conclude that the corresponding parts ∠A and ∠D are congruent.
Plan in action:
Exercise
1. Prove that FL O HN in the given diagram.
2. Prove that APUX – AQSY in the given figure.
3. Prove that AC = GE in the given diagram.
4. Write a two-column proof from the given diagram.
5. Prove that 21 22 from the given diagram with the given information. Given: MNKN, ZPMN
6. Prove that Z1 Z2 from the given diagram with the given information. Given: TS TV, SR_VW 1 RA
7. Find the measure of each angle in the given triangle. m2A=xo;m_B=(4x)”and m_C=(5x)”.
8 Find the measure of each angle in the given triangle. m2A=xo;mB=(5x)’and m2C=(x+19)o.
Concept Map
What have we learned:
- Understand and apply the SSS congruence postulate.
- Understand and apply SAS congruence postulate.
- Understand and apply the AAS congruence postulate.
- Understand and apply construction proof.
- Solve problems on different congruence of triangles.
- Solve problems on different congruence postulates.
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