Solution for the question - let f(x)={[x+1,0 0for all real numbers0

10th-Grade-Math---USA

Piecewise-Functions

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Question

Let $f left parenthesis x right parenthesis equals open curly brackets table attributes columnalign left end attributes row cell x plus 1 end cell cell space space space space 0 less or equal than x less than 4 end cell row cell x plus 4 end cell cell space space space space 4 less or equal than x less than 6 end cell row cell x plus 6 end cell cell space space space space 6 less or equal than x less or equal than 8 end cell end table close$ then the domain of f is

$1 \leq f (x) \leq 14$
$0 \leq x \leq 8$
for all real numbers
$0 \leq f (x)$

The correct answer is: $0 less or equal than x less or equal than 8$

Let $f left parenthesis x right parenthesis equals open curly brackets table attributes columnalign left end attributes row cell x plus 1 end cell cell space space space space space x less than 4 end cell row cell x plus 4 end cell cell space space space space space 4 less or equal than x less than 6 end cell row cell x plus 6 end cell cell space space space space space 6 less than x end cell end table close$ then the value of f(f(3)) is

10th-Grade-Math---USAPiecewise-Functions

Piecewise-Functions

10th-Grade-Math---USA

The value of ‘a’ in g(x) = a|x| with vertex (0, 0) & passing through (1, 3) is

10th-Grade-Math---USAPiecewise-Functions

Piecewise-Functions

10th-Grade-Math---USA

The value of $vertical line vertical line space x vertical line minus 7 vertical line$ for x = -4 is

10th-Grade-Math---USAPiecewise-Functions

Piecewise-Functions

10th-Grade-Math---USA

The domain that has the range of y = -x & y = -|x| the same is

10th-Grade-Math---USAPiecewise-Functions

Piecewise-Functions

10th-Grade-Math---USA

The value of f(2) + f(4) + f(11) + f(12) for the function
$f left parenthesis x right parenthesis equals open curly brackets table attributes columnalign left end attributes row cell 100 comma end cell cell 0 less than x less or equal than 4 end cell row cell 95 comma end cell cell 4 less than x less or equal than 8 end cell row cell 90 comma end cell cell 8 less than x less or equal than 12 end cell row cell 95 comma end cell cell 12 less than x less or equal than 16 end cell end table close$ is

10th-Grade-Math---USAPiecewise-Functions

Piecewise-Functions

10th-Grade-Math---USA

$open ceil negative 2.54 close ceil minus open floor negative 2.54 close floor$ =

10th-Grade-Math---USAPiecewise-Functions

Piecewise-Functions

10th-Grade-Math---USA

let $f left parenthesis x right parenthesis equals open curly brackets table attributes columnalign left end attributes row cell x minus 1 comma end cell cell x less than 4 end cell row cell negative x plus 4 comma end cell cell x greater or equal than 4 end cell end table close$ , the range of f is

10th-Grade-Math---USAPiecewise-Functions

Piecewise-Functions

10th-Grade-Math---USA

Let $f left parenthesis x right parenthesis equals open curly brackets table attributes columnalign left end attributes row cell x minus 1 comma end cell cell x less than 4 end cell row cell negative x plus 4 comma end cell cell x greater or equal than 4 end cell end table close$ then the value of f(4) is

10th-Grade-Math---USAPiecewise-Functions

Piecewise-Functions

10th-Grade-Math---USA

Let f(x) = |x|. The point that do not lie on the graph of the function is

10th-Grade-Math---USAPiecewise-Functions

Piecewise-Functions

10th-Grade-Math---USA

|-5.987| =

10th-Grade-Math---USAPiecewise-Functions

Piecewise-Functions

10th-Grade-Math---USA

The range of f(x) = |x| + 4 is

10th-Grade-Math---USAPiecewise-Functions

Piecewise-Functions

10th-Grade-Math---USA

From the graph identify the function.

10th-Grade-Math---USAPiecewise-Functions

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Let then the domain of f is

for all real numbers

The correct answer is:

Related Questions to study

Let then the value of f(f(3)) is

Let then the value of f(f(3)) is

The value of ‘a’ in g(x) = a|x| with vertex (0, 0) & passing through (1, 3) is

The value of ‘a’ in g(x) = a|x| with vertex (0, 0) & passing through (1, 3) is

The value of for x = -4 is

The value of for x = -4 is

The domain that has the range of y = -x & y = -|x| the same is

The domain that has the range of y = -x & y = -|x| the same is

The value of f(2) + f(4) + f(11) + f(12) for the functionis

The value of f(2) + f(4) + f(11) + f(12) for the functionis

=

=

The function from the graph is

The function from the graph is

=

=

=

=

let , the range of f is

let , the range of f is

Let then the value of f(4) is

Let then the value of f(4) is

Let f(x) = |x|. The point that do not lie on the graph of the function is

Let f(x) = |x|. The point that do not lie on the graph of the function is

|-5.987| =

|-5.987| =

The range of f(x) = |x| + 4 is

The range of f(x) = |x| + 4 is

From the graph identify the function.

From the graph identify the function.

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$1 \leq f (x) \leq 14$
$0 \leq x \leq 8$
for all real numbers
$0 \leq f (x)$

The correct answer is: $0 less or equal than x less or equal than 8$

The value of $vertical line vertical line space x vertical line minus 7 vertical line$ for x = -4 is

The value of $vertical line vertical line space x vertical line minus 7 vertical line$ for x = -4 is

$open ceil negative 2.54 close ceil minus open floor negative 2.54 close floor$ =

$open ceil negative 2.54 close ceil minus open floor negative 2.54 close floor$ =

$left floor negative 2.54 right floor$ =

$left floor negative 2.54 right floor$ =

$left ceiling negative 2.54 right ceiling$ =

$left ceiling negative 2.54 right ceiling$ =