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10th-Grade-Math---USA

Algebra

Easy

Question

Solve for the equation 2(x + 1) = 2(3 – 1).

4
2
1
$\frac{1}{2}$

The correct answer is: 1

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$The space sum space of space an space infinite space geometric space series space with space positive space terms space is space 3 space and space the space sum space of space the space cubes space of space its space terms space is space 27 over 19 space space Then space the space common space ratio space of space this space series space is$

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$The space sum space of space an space infinite space geometric space series space with space positive space terms space is space 3 space and space the space sum space of space the space cubes space of space its space terms space is space 27 over 19 space space Then space the space common space ratio space of space this space series space is$

$The space sum space of space an space infinite space geometric space series space with space positive space terms space is space 3 space and space the space sum space of space the space cubes space of space its space terms space is space 27 over 19 space space Then space the space common space ratio space of space this space series space is$

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$If space space lambda italic space space be space the space ratio space of space the space roots space of space the space quadratic space equation space in space straight x comma 3 m squared x squared plus m left parenthesis m minus 4 right parenthesis x plus 2 equals 0 space space then space space the space least space value space of space space straight m space space for space which space space lambda plus 1 over lambda equals 1 space space is$

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$Let space a subscript 1 comma a subscript 2 comma a subscript 3 italic. italic. italic. space be space straight a space harmonic space progression space such space that space a subscript 1 equals 5 space and space a subscript 20 equals 25 Least space value space of space straight n space which space a subscript n less than 0 space space is space space$

$Let space a subscript 1 comma a subscript 2 comma a subscript 3 italic. italic. italic. space be space straight a space harmonic space progression space such space that space a subscript 1 equals 5 space and space a subscript 20 equals 25 Least space value space of space straight n space which space a subscript n less than 0 space space is space space$

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$Let space a subscript 1 comma a subscript 2 comma a subscript 3 italic. italic. italic. space be space straight a space harmonic space progression space such space that space a subscript 1 equals 5 space and space a subscript 20 equals 25 Value space of space straight n space for space which space space a subscript n space space is space maximum space is$

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$Let space a subscript 1 comma a subscript 2 comma a subscript 3 midline horizontal ellipsis space space be space straight a space harmonic space progression space such space that space a subscript 1 equals 5 space space and space a subscript 20 equals 25 space space Value space of space straight n space for space which space a subscript n space space is space maximum space is space$

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$For space any space three space positive space real space numbers space straight a comma space straight b space and space straight c comma 9 open parentheses 25 a squared plus b squared close parentheses plus 25 open parentheses c squared minus 3 a c close parentheses equals 15 b left parenthesis 3 a plus c right parenthesis Then$

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$If space alpha not equal to beta text and end text alpha squared equals 5 alpha minus 3 comma beta squared equals 5 beta minus 3 space comma then space theequation space having space alpha divided by beta italic space a n d italic space beta divided by alpha italic space a s italic space i t s italic space r o o t s italic comma italic space i s$

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If $sum from n equals 1 to 5 of fraction numerator 1 over denominator n left parenthesis n plus 1 right parenthesis left parenthesis n plus 2 right parenthesis left parenthesis n plus 3 right parenthesis end fraction equals k over 3$ , then k is equal to

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