Solution for the question - the value of x in the figure is 14o11o19o 15o

9th-Grade-Math---USA

Congruent-Triangles

Easy

Question

The value of x in the figure is

15^o
19^o
11^o
14^o

The correct answer is: 14^o

The perimeter of the triangle is

9th-Grade-Math---USACongruent-Triangles

Congruent-Triangles

9th-Grade-Math---USA

$text If end text 5 over 2 straight x to the power of straight o comma 7 over 2 straight x to the power of straight o comma 60 to the power of straight o$ are the interior angles of $capital delta$ ABC, then the largest angle of $capital delta$ ABC is

9th-Grade-Math---USACongruent-Triangles

Congruent-Triangles

9th-Grade-Math---USA

In
$straight m angle straight A space equals$

9th-Grade-Math---USACongruent-Triangles

Congruent-Triangles

9th-Grade-Math---USA

The value of y is

9th-Grade-Math---USACongruent-Triangles

Congruent-Triangles

9th-Grade-Math---USA

If $angle A & angle B$ are supplementary, $space m angle A equals left parenthesis 4 x plus 6 right parenthesis degree comma m angle B equals left parenthesis 7 x minus 24 right parenthesis degree$ , then $m angle A$ is

9th-Grade-Math---USACongruent-Triangles

Congruent-Triangles

9th-Grade-Math---USA

Suppose $capital delta A B C approximately equal to capital delta E F D comma capital delta E F D approximately equal to capital delta G I H comma m angle A equals 90 degree & m angle F equals 20 degree$ , then $m angle H$ =

9th-Grade-Math---USACongruent-Triangles

Congruent-Triangles

9th-Grade-Math---USA

Classify the triangle $capital delta text DEF end text$ if $space m angle D equals left parenthesis 4 x plus 2 right parenthesis degree semicolon m angle E equals left parenthesis 6 x minus 30 right parenthesis degree & m angle F equals 3 x degree$ is

9th-Grade-Math---USACongruent-Triangles

Congruent-Triangles

9th-Grade-Math---USA

$text If in end text capital delta A B C m angle A equals x degree semicolon m angle B equals left parenthesis 5 x right parenthesis degree semicolon m angle C equals left parenthesis x plus 19 right parenthesis degree text , end text$ then the value of x is

9th-Grade-Math---USACongruent-Triangles

Congruent-Triangles

9th-Grade-Math---USA

$text If end text increment A B C approximately equal to capital delta D E F semicolon m angle A equals 70 degree comma m angle B equals 60 degree comma m angle C equals 50 degree comma m angle D equals left parenthesis 3 x plus 10 right parenthesis degree$ , then the value of x is

9th-Grade-Math---USACongruent-Triangles

Congruent-Triangles

9th-Grade-Math---USA

The value of x is

9th-Grade-Math---USACongruent-Triangles

Congruent-Triangles

9th-Grade-Math---USA

The postulate we use to prove $increment A B C approximately equal to capital delta H J K$ is

9th-Grade-Math---USACongruent-Triangles

Congruent-Triangles

9th-Grade-Math---USA

The value of x is

9th-Grade-Math---USACongruent-Triangles

Have a query? Ask a Tutor!!

Can’t find what you’re looking for?

The value of x in the figure is

15o 19o 11o14o

The correct answer is: 14o

Related Questions to study

The perimeter of the triangle is

The perimeter of the triangle is

are the interior angles of ABC, then the largest angle of ABC is

are the interior angles of ABC, then the largest angle of ABC is

In

In

The value of y is

The value of y is

If are supplementary,, then is

If are supplementary,, then is

Suppose , then =

Suppose , then =

Classify the triangle if is

Classify the triangle if is

The value of x in the diagram if it is an isosceles triangle is

The value of x in the diagram if it is an isosceles triangle is

The value of x & y are

The value of x & y are

The value of x & y in the diagram are

The value of x & y in the diagram are

then the value of x is

then the value of x is

, then the value of x is

, then the value of x is

The value of x is

The value of x is

The postulate we use to prove is

The postulate we use to prove is

The value of x is

The value of x is

With Turito Academy.

With Turito Foundation.

Get an Expert Advice From Turito.

Turito Academy

With Turito Academy.

Test Prep

With Turito Foundation.

Courses

Quick Links

15^o
19^o
11^o
14^o

The correct answer is: 14^o

$text If end text 5 over 2 straight x to the power of straight o comma 7 over 2 straight x to the power of straight o comma 60 to the power of straight o$ are the interior angles of $capital delta$ ABC, then the largest angle of $capital delta$ ABC is

$text If end text 5 over 2 straight x to the power of straight o comma 7 over 2 straight x to the power of straight o comma 60 to the power of straight o$ are the interior angles of $capital delta$ ABC, then the largest angle of $capital delta$ ABC is

In
$straight m angle straight A space equals$

In
$straight m angle straight A space equals$

If $angle A & angle B$ are supplementary, $space m angle A equals left parenthesis 4 x plus 6 right parenthesis degree comma m angle B equals left parenthesis 7 x minus 24 right parenthesis degree$ , then $m angle A$ is

If $angle A & angle B$ are supplementary, $space m angle A equals left parenthesis 4 x plus 6 right parenthesis degree comma m angle B equals left parenthesis 7 x minus 24 right parenthesis degree$ , then $m angle A$ is

Suppose $capital delta A B C approximately equal to capital delta E F D comma capital delta E F D approximately equal to capital delta G I H comma m angle A equals 90 degree & m angle F equals 20 degree$ , then $m angle H$ =

Suppose $capital delta A B C approximately equal to capital delta E F D comma capital delta E F D approximately equal to capital delta G I H comma m angle A equals 90 degree & m angle F equals 20 degree$ , then $m angle H$ =

Classify the triangle $capital delta text DEF end text$ if $space m angle D equals left parenthesis 4 x plus 2 right parenthesis degree semicolon m angle E equals left parenthesis 6 x minus 30 right parenthesis degree & m angle F equals 3 x degree$ is

Classify the triangle $capital delta text DEF end text$ if $space m angle D equals left parenthesis 4 x plus 2 right parenthesis degree semicolon m angle E equals left parenthesis 6 x minus 30 right parenthesis degree & m angle F equals 3 x degree$ is

$text If in end text capital delta A B C m angle A equals x degree semicolon m angle B equals left parenthesis 5 x right parenthesis degree semicolon m angle C equals left parenthesis x plus 19 right parenthesis degree text , end text$ then the value of x is

$text If in end text capital delta A B C m angle A equals x degree semicolon m angle B equals left parenthesis 5 x right parenthesis degree semicolon m angle C equals left parenthesis x plus 19 right parenthesis degree text , end text$ then the value of x is

$text If end text increment A B C approximately equal to capital delta D E F semicolon m angle A equals 70 degree comma m angle B equals 60 degree comma m angle C equals 50 degree comma m angle D equals left parenthesis 3 x plus 10 right parenthesis degree$ , then the value of x is

$text If end text increment A B C approximately equal to capital delta D E F semicolon m angle A equals 70 degree comma m angle B equals 60 degree comma m angle C equals 50 degree comma m angle D equals left parenthesis 3 x plus 10 right parenthesis degree$ , then the value of x is

The postulate we use to prove $increment A B C approximately equal to capital delta H J K$ is

The postulate we use to prove $increment A B C approximately equal to capital delta H J K$ is