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Chemistry-

General

Easy

Question

$t subscript 1 divided by 2 end subscript equals$ constant confirms the first order of the reaction as one $a to the power of 2 end exponent t subscript 1 divided by 2 end subscript equals$ constant confirms that the reaction is of

Zero order
First order
Second order
Third order

The correct answer is: Third order

For $n$ th order, $t subscript 1 divided by 2 end subscript proportional to open parentheses a close parentheses to the power of 1 minus n end exponent$
$rightwards double arrow blank fraction numerator t subscript 1 divided by 2 end subscript over denominator open parentheses a close parentheses to the power of 1 minus n end exponent end fraction$ or $t subscript 1 divided by 2 end subscript cross times open parentheses a close parentheses to the power of n minus 1 end exponent equals$ Constant
$therefore$ Given $t subscript 1 divided by 2 end subscript cross times open parentheses a close parentheses to the power of n minus 1 end exponent equals t subscript 1 divided by 2 end subscript open parentheses a close parentheses to the power of 2 end exponent$
$rightwards double arrow open parentheses a close parentheses to the power of n minus 1 end exponent equals open parentheses a close parentheses to the power of 2 end exponent$
$therefore blank n minus 1 equals 2 blank rightwards double arrow n equals 3$
Hence, third order reaction

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Chemistry-General

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parallel

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parallel

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