Chemistry-
General
Easy

Question

Compound ‘A’ (molecular formula C3H8O) is treated with acidified K2Cr2O7 to form a product

  1. CH3CH2CH = NNHCONH2    
  2. (molecular formula C3H6O). ‘B’ forms a shining silver mirror on warming with ammoniacal AgNO3. ‘B’ when treated with an aq. Solution to H2NCONHNH2, HCl & Sodium acetate gives a product ‘C’. Identify the product ‘C’.    
  3.    
  4. CH3CH2CH = NCONHNH2    

The correct answer is: CH3CH2CH = NNHCONH2

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