Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Offsite Campus Turito Championship

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

Chemistry-

General

Easy

Question

Consider the reaction: $blank C l subscript 2 end subscript left parenthesis a q right parenthesis plus H subscript 2 end subscript S left parenthesis a q right parenthesis ⟶ S left parenthesis s right parenthesis plus 2 H to the power of plus end exponent left parenthesis a q right parenthesis plus 2 C l to the power of minus end exponent left parenthesis a q right parenthesis$ The rate equation for this reaction is : $blank R a t e blank equals k open square brackets C l subscript 2 end subscript close square brackets open square brackets H subscript 2 end subscript S close square brackets$ Which of these mechanisms is/are consistent with this rate equation ?

neither A nor B
A only
B only
both A and B

The correct answer is: A only

Related Questions to study

Two particles move in a uniform gravitational field with an acceleration g. At the initial moment the particles were located at one point and moved with velocities V₁ = 1 m/s and V₂ = 4 m/s horizontally in opposite directions. The distance between the particles at the moment when their velocity vectors become mutually perpendicular is (g=10m/s²)

Two particles move in a uniform gravitational field with an acceleration g. At the initial moment the particles were located at one point and moved with velocities V₁ = 1 m/s and V₂ = 4 m/s horizontally in opposite directions. The distance between the particles at the moment when their velocity vectors become mutually perpendicular is (g=10m/s²)

Physics-General

An endothermic reaction with high activation energy for the forward reaction is given by the diagram:

An endothermic reaction with high activation energy for the forward reaction is given by the diagram:

Chemistry-General

Graph between concentration of the product' x' and time' t' for $A rightwards arrow B$ is given ahead:
The graph between $negative fraction numerator d left square bracket A right square bracket over denominator d t end fraction$ and time wil1 be of the type:

Graph between concentration of the product' x' and time' t' for $A rightwards arrow B$ is given ahead:
The graph between $negative fraction numerator d left square bracket A right square bracket over denominator d t end fraction$ and time wil1 be of the type:

Chemistry-General

parallel

Following is the graph between $left parenthesis a minus x right parenthesis to the power of negative 1 end exponent$ and time t for second order reaction. $theta equals t a n to the power of negative 1 end exponent invisible function application left parenthesis 1 divided by 2 right parenthesis semicolon O A equals 2 L m o l to the power of negative 1 end exponent$ hence rate at the start of reaction will be:

Following is the graph between $left parenthesis a minus x right parenthesis to the power of negative 1 end exponent$ and time t for second order reaction. $theta equals t a n to the power of negative 1 end exponent invisible function application left parenthesis 1 divided by 2 right parenthesis semicolon O A equals 2 L m o l to the power of negative 1 end exponent$ hence rate at the start of reaction will be:

Chemistry-General

Following is the graph between log tll2 and log a (a = initial concentration) for a given
reaction at $27 to the power of ring operator end exponent$ e. Hence, order is:

Following is the graph between log tll2 and log a (a = initial concentration) for a given
reaction at $27 to the power of ring operator end exponent$ e. Hence, order is:

Chemistry-General

For the reaction $N H subscript 4 end subscript superscript plus end superscript plus O C N ⟶ N H subscript 2 end subscript C O N H subscript 2 end subscript$ the probable mechanism is,
$table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell NH subscript 4 superscript plus plus OCN to the power of minus not stretchy rightwards harpoon over leftwards harpoon NH subscript 4 OCN end cell row cell text and end text space of 1em NH subscript 4 OCN not stretchy ⟶ NH subscript 2 CONH subscript 2 space of 1em text (slow) end text end cell end table$ The rate law will be:

For the reaction $N H subscript 4 end subscript superscript plus end superscript plus O C N ⟶ N H subscript 2 end subscript C O N H subscript 2 end subscript$ the probable mechanism is,
$table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell NH subscript 4 superscript plus plus OCN to the power of minus not stretchy rightwards harpoon over leftwards harpoon NH subscript 4 OCN end cell row cell text and end text space of 1em NH subscript 4 OCN not stretchy ⟶ NH subscript 2 CONH subscript 2 space of 1em text (slow) end text end cell end table$ The rate law will be:

Chemistry-General

parallel

A drop of solution (volume 0.05 mL) contains $3 cross times 10 to the power of negative 6 end exponent$ mole of W. If the rate constant of disappearance of H+ is 107 mol $text litre end text to the power of negative 1 end exponent sec to the power of negative 1 end exponent$ , how long would it take for W in the drop tell disappear?

A drop of solution (volume 0.05 mL) contains $3 cross times 10 to the power of negative 6 end exponent$ mole of W. If the rate constant of disappearance of H+ is 107 mol $text litre end text to the power of negative 1 end exponent sec to the power of negative 1 end exponent$ , how long would it take for W in the drop tell disappear?

Chemistry-General

P₄ + 5O₂ ¾ → X $Error converting from MathML to accessible text.$ Y, Y is

P₄ + 5O₂ ¾ → X $Error converting from MathML to accessible text.$ Y, Y is

Chemistry-General

Cu²⁺ + 2e^– ¾® Cu; log[Cu²⁺] vs E_red graph is of the type shown in figure where OA = 0.34V, then electrode potential of the half cell of Cu/Cu²⁺ (0.1 M) will be

Cu²⁺ + 2e^– ¾® Cu; log[Cu²⁺] vs E_red graph is of the type shown in figure where OA = 0.34V, then electrode potential of the half cell of Cu/Cu²⁺ (0.1 M) will be

Chemistry-General

parallel

Which statement is correct for alkaline earth metals

Which statement is correct for alkaline earth metals

Chemistry-General

The incorrect statement is

The incorrect statement is

Chemistry-General

Ketone can be prepared by

Ketone can be prepared by

Chemistry-General

parallel

Chemistry-General

Chemistry-General

Identify X in the sequence C₃H₉N $Error converting from MathML to accessible text.$ C₃H₈O $Error converting from MathML to accessible text.$ C₃H₆O₂

Identify X in the sequence C₃H₉N $Error converting from MathML to accessible text.$ C₃H₈O $Error converting from MathML to accessible text.$ C₃H₆O₂

Chemistry-General

parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.