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Physics-

General

Easy

Question

Two particles move in a uniform gravitational field with an acceleration g. At the initial moment the particles were located at one point and moved with velocities V₁ = 1 m/s and V₂ = 4 m/s horizontally in opposite directions. The distance between the particles at the moment when their velocity vectors become mutually perpendicular is (g=10m/s²)

4 m
3 m
2 m
1

The correct answer is: 3 m

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