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Chemistry

General

Easy

Question

Formalin is

Solution of fructose
40% aq. sol. Of HCHO
$40 % H C H O + 60 % C H_{3} C H O$
None of the above

The correct answer is: 40% aq. sol. Of HCHO

Related Questions to study

Claisen condensation is not given by

Claisen condensation is not given by

ChemistryGeneral

On heating with aqueous alkali, chloroform yields:

On heating with aqueous alkali, chloroform yields:

ChemistryGeneral

The correct order of increasing acid strength of the compounds
$left parenthesis A right parenthesis C H subscript 3 C O O H left parenthesis B right parenthesis M e O C H subscript 2 C O O H left parenthesis C right parenthesis C F subscript 3 C O O H$
D)
is:

The correct order of increasing acid strength of the compounds
$left parenthesis A right parenthesis C H subscript 3 C O O H left parenthesis B right parenthesis M e O C H subscript 2 C O O H left parenthesis C right parenthesis C F subscript 3 C O O H$
D)
is:

ChemistryGeneral

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The structural formula of the compound isomeric with acetone is:

The structural formula of the compound isomeric with acetone is:

ChemistryGeneral

Complete the following reaction,

Complete the following reaction,

ChemistryGeneral

The product of the following reaction

The product of the following reaction

ChemistryGeneral

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Organic compounds are studied separately from inorganic compounds because:

Organic compounds are studied separately from inorganic compounds because:

ChemistryGeneral

An aliphatic hydroxy acid is:

An aliphatic hydroxy acid is:

ChemistryGeneral

Acetone and acetaldehyde can be identified by treatment with:

Acetone and acetaldehyde can be identified by treatment with:

ChemistryGeneral

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Which of the following statement is correct?

Which of the following statement is correct?

ChemistryGeneral

What is the product in following cross Claisen condensation?
$straight C subscript 2 straight H subscript 5 COOC subscript 2 straight H subscript 5 plus stack COOC subscript 2 straight H subscript 5 with COOC subscript 2 straight H subscript 5 below fraction numerator straight C subscript 2 straight H subscript 5 ONa over denominator straight H to the power of plus end fraction not stretchy rightwards arrow ?$

What is the product in following cross Claisen condensation?
$straight C subscript 2 straight H subscript 5 COOC subscript 2 straight H subscript 5 plus stack COOC subscript 2 straight H subscript 5 with COOC subscript 2 straight H subscript 5 below fraction numerator straight C subscript 2 straight H subscript 5 ONa over denominator straight H to the power of plus end fraction not stretchy rightwards arrow ?$

ChemistryGeneral

Match the columns
Column-I Column-II
A) Coordinated water (p) $open square brackets Cu open parentheses straight H subscript 2 straight O close parentheses subscript 4 close square brackets to the power of 4 plus end exponent SO subscript 4 superscript 2 minus end superscript times straight H subscript 2 straight O$
B) Interstitial water (q) $straight C subscript 17 straight H subscript 35 COONa$
C) Hydrogen-bonded water (r) $BaCl subscript 2 times 2 straight H subscript 2 straight O$
(s) $open square brackets Cr open parentheses straight H subscript 2 straight O close parentheses subscript 6 close square brackets to the power of 3 plus end exponent 3 Cl to the power of minus$

Match the columns
Column-I Column-II
A) Coordinated water (p) $open square brackets Cu open parentheses straight H subscript 2 straight O close parentheses subscript 4 close square brackets to the power of 4 plus end exponent SO subscript 4 superscript 2 minus end superscript times straight H subscript 2 straight O$
B) Interstitial water (q) $straight C subscript 17 straight H subscript 35 COONa$
C) Hydrogen-bonded water (r) $BaCl subscript 2 times 2 straight H subscript 2 straight O$
(s) $open square brackets Cr open parentheses straight H subscript 2 straight O close parentheses subscript 6 close square brackets to the power of 3 plus end exponent 3 Cl to the power of minus$

ChemistryGeneral

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Match the columns.
Column I Column II
$text A) end text fraction numerator p K subscript a comma H subscript 2 O plus p K subscript b comma H subscript 2 end subscript O end subscript over denominator 2 end fraction text at end text 25 to the power of ring operator C open parentheses d subscript text water end text end subscript equals 1.0 straight g divided by ml close parentheses$ $text (P) end text fraction numerator straight p K subscript straight w over denominator 2 end fraction$
$text B) end text pH text of end text CH subscript 3 COONH subscript 4 left parenthesis aq right parenthesis open parentheses K subscript straight a comma CH comma straight c straight infinity OH end subscript equals K subscript straight b comma NH comma OH end subscript close parentheses$ $text (Q) end text 16 minus log invisible function application 1.8$
$text C) end text pH text of pure water at end text 320 straight K text . end text$ $left parenthesis straight R right parenthesis minus log invisible function application K subscript straight a comma straight H comma O end subscript$
$text (S) end text less than 7.0$

Match the columns.
Column I Column II
$text A) end text fraction numerator p K subscript a comma H subscript 2 O plus p K subscript b comma H subscript 2 end subscript O end subscript over denominator 2 end fraction text at end text 25 to the power of ring operator C open parentheses d subscript text water end text end subscript equals 1.0 straight g divided by ml close parentheses$ $text (P) end text fraction numerator straight p K subscript straight w over denominator 2 end fraction$
$text B) end text pH text of end text CH subscript 3 COONH subscript 4 left parenthesis aq right parenthesis open parentheses K subscript straight a comma CH comma straight c straight infinity OH end subscript equals K subscript straight b comma NH comma OH end subscript close parentheses$ $text (Q) end text 16 minus log invisible function application 1.8$
$text C) end text pH text of pure water at end text 320 straight K text . end text$ $left parenthesis straight R right parenthesis minus log invisible function application K subscript straight a comma straight H comma O end subscript$
$text (S) end text less than 7.0$

ChemistryGeneral

Match the columns.
Column I                                                      Column II
A) NaCl (P) Cationic hydrolysis
B) Na₂CO₃                                              (Q) Anionic hydrolysis
C) NH₄Cl (R) pH = 7.0 at 25^oC
D) CH₃COONH₄                                      (S) pH < 7.0 at 25^oC
(T) pH > 7.0 at 25^oC
K_a,CH₃COOH = K_b,NH₄OH

Match the columns.
Column I                                                      Column II
A) NaCl (P) Cationic hydrolysis
B) Na₂CO₃                                              (Q) Anionic hydrolysis
C) NH₄Cl (R) pH = 7.0 at 25^oC
D) CH₃COONH₄                                      (S) pH < 7.0 at 25^oC
(T) pH > 7.0 at 25^oC
K_a,CH₃COOH = K_b,NH₄OH

ChemistryGeneral

Column I (pH value) Column II (Solution)
A) 5.0 (P) pH at which Mg(OH)₂ just start precipitating from 2.0×10⁻³ M-Mg²⁺solution (K_sp of Mg(OH)₂ = 2 × 10⁻⁶ M³ ).
B) 9.0 (Q) Maximum pH at which 0.1 mole of Al(OH)₃ dissolves completely as Al³⁺ in 1 L solution (K_sp of Al(OH)₃ = 1 × 10⁻²⁸ M⁴).
C) 12.5 (R) pH at which 0.1 M-CH₃COOH dissociates                                                             1000/11% (K_a of CH₃COOH = 1.0×10⁻⁵M).
D) 6.0 (S) pH of 0.001 M-HA (weak acid) solution (pK_a of                                                             HA = pKb of A⁻).
(T) pH of 3×10⁻⁵ M-CaA₂ solution (CaA₂ dissociates                                                             completely in water; Ka of HA = 5 × 10⁻⁹).

Column I (pH value) Column II (Solution)
A) 5.0 (P) pH at which Mg(OH)₂ just start precipitating from 2.0×10⁻³ M-Mg²⁺solution (K_sp of Mg(OH)₂ = 2 × 10⁻⁶ M³ ).
B) 9.0 (Q) Maximum pH at which 0.1 mole of Al(OH)₃ dissolves completely as Al³⁺ in 1 L solution (K_sp of Al(OH)₃ = 1 × 10⁻²⁸ M⁴).
C) 12.5 (R) pH at which 0.1 M-CH₃COOH dissociates                                                             1000/11% (K_a of CH₃COOH = 1.0×10⁻⁵M).
D) 6.0 (S) pH of 0.001 M-HA (weak acid) solution (pK_a of                                                             HA = pKb of A⁻).
(T) pH of 3×10⁻⁵ M-CaA₂ solution (CaA₂ dissociates                                                             completely in water; Ka of HA = 5 × 10⁻⁹).

ChemistryGeneral

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