Chemistry
Grade-9
Easy
Question
If 2.74gm of metal oxide contains 1.53gm of metal, then what will be the empirical formula of vanadium oxide?
- VO
- VO2
- V2O5
- V3O7
Hint:
% of metal in the oxide is 55.8%, oxygen % is 44.2%
The correct answer is: V2O5
2.74gm of vanadium oxide contains 1.53gm of metal. % of metal in the oxide is 55.8%, oxygen % is 44.2%
Let us consider the formula to be (VO)n. Atomic mass of vanadium is 51.
Number of atoms of Vanadium = 55.8
51 = 1.09
Number of atoms of oxygen = 44.22.76 = 2.76
Simplest ratio for V = 1.09/1.09 = 1
Simplest ratio for O = 2.76/1.09 = 2.5
Empirical formula = 2:5
The empirical formula of vanadium oxide = V2O5
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