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Chemistry-

General

Easy

Question

If the composition of the system does not change with time, the system is said to be in chemical equilibrium. It is the state in which net reaction of a system is zero. In another words we can say that in reversible reactions, a stage is reached when the rate of transformation of reactants into products equals to the rate of transformation of products into reactants. At this stage, the composition of reactants and products does not change with time. This does not mean that the reaction has ceased, as both reverse and forward reactions are still taking place but with equal rate. Such equilibria are called dynamic equilirbria.
Let us consider a reaction of the type
A (g) + B(g) $Error converting from MathML to accessible text.$ C(g) + D(g)
$K subscript C end subscript equals fraction numerator open square brackets C close square brackets open square brackets D close square brackets over denominator open square brackets A close square brackets open square brackets B close square brackets end fraction$
where Kc is equilibrium constant which is equal to the ratio of the concentrations of the product to reactants
$K subscript P end subscript equals fraction numerator P subscript C end subscript cross times P subscript D end subscript over denominator P subscript A end subscript cross times P subscript B end subscript end fraction$
where KP is the equilibrium constant which is equal to the ratio of partial pressure of products to reactants. The relation between KP and KC is as follows.
KP = Kc(RT)^Dⁿ
Determine K_C for the reaction $fraction numerator 1 over denominator 2 end fraction N subscript 2 end subscript left parenthesis g right parenthesis plus fraction numerator 1 over denominator 2 end fraction O subscript 2 end subscript left parenthesis g right parenthesis plus fraction numerator 1 over denominator 2 end fraction text B end text text r end text subscript 2 end subscript left parenthesis g right parenthesis$ $Error converting from MathML to accessible text.$ NOBr(g) from the following information at 298 K
2NO (g) $Error converting from MathML to accessible text.$ N2 (g) + O2 (g) K1 = 2.4 × 1030
$text NO end text left parenthesis g right parenthesis plus fraction numerator 1 over denominator 2 end fraction text B end text text r end text subscript 2 end subscript left parenthesis g right parenthesis$ $Error converting from MathML to accessible text.$ NOBr(g)K2 = 1.4

3.15 × 10-9
6.35 × 5 10-18
9.03 × 10-16
17 × 10-17

The correct answer is: 9.03 × 10-16

2NO $Error converting from MathML to accessible text.$ N₂ + O₂ K₁
NO $Error converting from MathML to accessible text.$ $fraction numerator 1 over denominator 2 end fraction N subscript 2 end subscript$ + $fraction numerator 1 over denominator 2 end fraction O subscript 2 end subscript$ $square root of K subscript 1 end subscript end root$
$fraction numerator 1 over denominator 2 end fraction N subscript 2 end subscript plus fraction numerator 1 over denominator 2 end fraction O subscript 2 end subscript$ $Error converting from MathML to accessible text.$ NO $fraction numerator 1 over denominator square root of K subscript 1 end subscript end root end fraction$ . . . . .(i)
NO + $fraction numerator 1 over denominator 2 end fraction B r subscript 2 end subscript$ $Error converting from MathML to accessible text.$ NOBr K₂. . . . .(ii)
by adding eq. (i) and (ii) we get
$fraction numerator 1 over denominator 2 end fraction N subscript 2 end subscript plus fraction numerator 1 over denominator 2 end fraction O subscript 2 end subscript$ + $fraction numerator 1 over denominator 2 end fraction B r subscript 2 end subscript$ $Error converting from MathML to accessible text.$ NOBr $fraction numerator 1 over denominator square root of K subscript 1 end subscript end root end fraction cross times K subscript 2 end subscript$

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