Chemistry
Grade-8
Easy
Question
In the given chemical reaction, when methane reacts with oxygen, the product obtained are carbon monoxide and water. If the total mass of reactant molecules is 80 g, then find out the total mass of CO2 and H2O obtained in this reaction.
Mass of CO2(g)
Mass of H2O(g)
44
30
Mass of CO2(g)
Mass of H2O(g)
40
32
Mass of CO2(g)
Mass of H2O(g)
54
24
Mass of CO2(g)
Mass of H2O(g)
44
36
| Mass of CO2(g) | Mass of H2O(g) |
|
44 |
30 |
| Mass of CO2(g) | Mass of H2O(g) |
|
40 |
32 |
| Mass of CO2(g) | Mass of H2O(g) |
|
54 |
24 |
| Mass of CO2(g) | Mass of H2O(g) |
|
44 |
36 |
Hint:
The chemical reaction follows the law of conservation of mass.
The correct answer is:
Mass of CO2(g)
Mass of H2O(g)
44
36
44
36
Mass of CO2(g)
Mass of H2O(g)
44
36
The reaction follows the law of conservation of mass.
The reaction is as follows:
CH2 + 2H2 = CO2 +2H2O
As we know the mass of reactants is always equal to the mass of products.
Mass of reactants= 80g (given)
Substituting this value,
80g= [(1x12)+ (2x16)] + 2x [(2x1)+(1x16)]
80g = 44g +36g
So, 44g of carbon dioxide was formed, and 36g of water.
44
36
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