Chemistry-
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Question

The correct order of dipole moments of HF, H subscript 2 end subscript S and H subscript 2 end subscript O is

  1. H F less than H subscript 2 end subscript S less than H subscript 2 end subscript O    
  2. H F less than H subscript 2 end subscript S greater than H subscript 2 end subscript O    
  3. H F greater than H subscript 2 end subscript S greater than H subscript 2 end subscript O    
  4. H F greater than H subscript 2 end subscript O less than H subscript 2 end subscript S    

The correct answer is: H F greater than H subscript 2 end subscript S greater than H subscript 2 end subscript O


    H minus F blank mu equals 1.91 blank D
    H subscript 2 end subscript O blank open parentheses theta equals 104.5 degree close parentheses equals 1.84 blank D
    H subscript 2 end subscript S blank open parentheses theta equals 92 degree close parentheses equals 1.88 blank D

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