Chemistry-
General
Easy

Question

I)1, 2-dihydroxy benzene
II) 1, 3-dihydroxy benzene
III) 1, 4-dihydroxy benzene
IV) Hydroxy benzene The increasing order of boiling points of above mentioned alcohols is

  1. I less than I I less than I I I less than I V    
  2. I less than I I less than I V less than I I I    
  3. I V less than I less than I I less than I I I    
  4. I V less than I I less than I less than I I I    

The correct answer is: I V less than I less than I I less than I I I


    1, 4-dihydroxy benzene shows the highest boiling point among given compounds because it forms strong intermolecular hydrogen bonds (It does not form intermolecular H-bonding.)

    Order of H-bonding in o, m and p-isomers of a compound is given below
    Intermolecular H-bonding, o less than m less than p-isomers
    intermolecular H-bonding
    o greater than m greater than pisomers.
    Hydroxy benzene do not form a chain of H-bonding . Hence, intermolecular H-bond is stronger than intermolecular H-bonds, so the stability of 1, 4-dihydroxy benzene is highest. Hence its boiling point is highest. The increasing order of the boiling points of the given compound is
    I V less than I less than I I less than I I I

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