Chemistry-
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Question

The equilibrium constants for the reactions are: The equilibrium constant for H subscript 3 end subscript P O subscript 4 end subscript rightwards harpoon over leftwards harpoon 3 H to the power of plus end exponent plus P O subscript 4 end subscript superscript 3 minus end superscript will be:

  1. K subscript 1 end subscript divided by K subscript 2 end subscript K subscript 3 end subscript  
  2. K subscript 1 end subscript cross times K subscript 2 end subscript cross times K subscript 3 end subscript  
  3. K subscript 2 end subscript divided by K subscript 1 end subscript K subscript 3 end subscript  
  4. K subscript 1 end subscript plus K subscript 2 end subscript plus K subscript 3 end subscript  

The correct answer is: K subscript 1 end subscript cross times K subscript 2 end subscript cross times K subscript 3 end subscript


    K subscript 1 end subscript equals blank fraction numerator open square brackets H to the power of plus end exponent close square brackets left square bracket H subscript 2 end subscript P O subscript 4 end subscript superscript minus end superscript right square bracket over denominator left square bracket H subscript 3 end subscript P O subscript 4 end subscript right square bracket end fraction semicolon K subscript 2 end subscript equals blank fraction numerator open square brackets H to the power of plus end exponent close square brackets left square bracket H P O subscript 4 end subscript superscript 2 minus end superscript right square bracket over denominator left square bracket H subscript 2 end subscript P O subscript 4 end subscript superscript minus end superscript right square bracket end fraction
    K subscript 3 end subscript equals blank fraction numerator open square brackets H to the power of plus end exponent close square brackets left square bracket P O subscript 4 end subscript superscript 3 minus end superscript right square bracket over denominator left square bracket H P O subscript 4 end subscript superscript 2 minus end superscript right square bracket end fraction Multiplying these three
    K subscript 1 blank end subscript x blank K subscript 2 end subscript blank x blank K subscript 3 end subscript equals blank fraction numerator open square brackets H to the power of plus end exponent close square brackets to the power of 3 end exponent left square bracket P O subscript 4 end subscript superscript 3 minus end superscript right square bracket over denominator left square bracket H subscript 3 end subscript P O subscript 4 end subscript right square bracket end fraction

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