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Chemistry-

General

Easy

Question

The ionization constant of ammonium hydroxide is $1.77 cross times 10 to the power of negative 5 end exponent$ at $298 text end text K$ . Hydrolysis constant of ammonium chloride is:

$5.65 \times 10^{- 12}$
$5.65 \times 10^{- 10}$
$6.50 \times 10^{- 12}$
$5.65 \times 10^{- 13}$

The correct answer is: $5.65 cross times 10 to the power of negative 10 end exponent$

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