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Chemistry-

General

Easy

Question

The order of magnitude of ionic radii of ions $N a to the power of plus end exponent comma M g to the power of 2 plus end exponent comma A l to the power of 3 plus end exponent$ and $S i to the power of 4 plus end exponent$ is

(a) $N a^{+} < M g^{2 +} < A l^{3 +} < S i^{4 +}$
$M g^{2 +} > N a^{+} > A l^{3 +} > S i^{4 +}$
(c) $A l^{3 +} > N a^{+} > S i^{4 +} > M g^{2 +}$
$N a^{+} > M g^{2 +} > A l^{3 +} > S i^{4 +}$

The correct answer is: $N a to the power of plus end exponent greater than M g to the power of 2 plus end exponent greater than A l to the power of 3 plus end exponent greater than S i to the power of 4 plus end exponent$

$N a to the power of plus end exponent greater than M g to the power of 2 plus end exponent greater than A l to the power of 3 plus end exponent greater than S i to the power of 4 plus end exponent$ . All are isoelectronic but nuclear charge per electron is greatest for $S i to the power of 4 plus end exponent$ . So it has smallest size and nuclear charge per electron for $N a to the power of plus end exponent$ is smallest. So it has largest size.

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