Maths-
General
Easy

Question

How many 6 digit number can be formed using the digit 1, 2, 3, 4, 5 and 6 that have at least two of the digits the same:

  1. 6(65 –5!)  
  2. 66  
  3. 6!  
  4. 66 – 5!  

The correct answer is: 6(65 –5!)


    required = total – All different digits
    = 66 – 6! = 6(65 – 5!)

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