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The removal of two atoms or groups, one generally hydrogen open parentheses H to the power of plus end exponent close parentheses and the other a leaving group open parentheses L to the power of minus end exponent close parentheses resulting in the formation of unsaturated compound is known as elimination reaction.

In E subscript 1 end subscript (elimination) reactions, the C minus L bond is broken heterolytic ally (in step 1) to form a carbocation (as in S subscript N to the power of 1 end exponent end subscript reaction) in which open parentheses L to the power of minus end exponent close) is lost (rate determining step). The carbocation (in step 2) loses a proton from the beta-carbon atom by a base (nucleophile) to form an alkene. E subscript 1 end subscript reaction is favoured in compounds in which the leaving group is at secondary open parentheses 2 to the power of ring operator end exponent close parentheses to the power of ´ end exponent or tertiary open parentheses 3 to the power of ring operator end exponent close parentheses position. In E subscript 2 end subscript text end text left parenthesis e l i m i n a t i o n right parenthesis text end text r e a c t i o n s comma text end text t w o text end text s i g m a text end text b o n d s text end text a r e text end text b r o k e n text end text a n d text end text a formed simultaneously. E subscript 2 end subscript reactions occur in one step through a transition state.

E subscript 2 end subscript reactions are most common in haloalkanes (particularly, 1 to the power of ring operator end exponent) and better the leaving group higher is the E subscript 1 end subscript reaction. In E subscript 2 end subscript reactions, both the leaving groups should be antiplanar.
E subscript 1 end subscript cb (Elimination unimolecular conjugate base) reaction involves the removal of proton by. a conjugate base (step 1) to produce carbanion which loses a leaving group to form an alkene (step 2) and is a slow step.
2-Bromobutane on heating with concentrated solution of alcoholic KOH gives major product as:

  1. but-1-ene    
  2. but-2-ene    
  3. bUtlln-2- ol    
  4. 2-methylpropene    

The correct answer is: but-2-ene

Related Questions to study

General
Chemistry-

The removal of two atoms or groups, one generally hydrogen open parentheses H to the power of plus end exponent close parentheses and the other a leaving group open parentheses L to the power of minus end exponent close parentheses resulting in the formation of unsaturated compound is known as elimination reaction.

In E subscript 1 end subscript (elimination) reactions, the C minus L bond is broken heterolytic ally (in step 1) to form a carbocation (as in S subscript N to the power of 1 end exponent end subscript reaction) in which open parentheses L to the power of minus end exponent close) is lost (rate determining step). The carbocation (in step 2) loses a proton from the beta-carbon atom by a base (nucleophile) to form an alkene. E subscript 1 end subscript reaction is favoured in compounds in which the leaving group is at secondary open parentheses 2 to the power of ring operator end exponent close parentheses to the power of ´ end exponent or tertiary open parentheses 3 to the power of ring operator end exponent close parentheses position. In E subscript 2 end subscript text end text left parenthesis e l i m i n a t i o n right parenthesis text end text r e a c t i o n s comma text end text t w o text end text s i g m a text end text b o n d s text end text a r e text end text b r o k e n text end text a n d text end text a formed simultaneously. E subscript 2 end subscript reactions occur in one step through a transition state.

E subscript 2 end subscript reactions are most common in haloalkanes (particularly, 1 to the power of ring operator end exponent) and better the leaving group higher is the E subscript 1 end subscript reaction. In E subscript 2 end subscript reactions, both the leaving groups should be antiplanar.
E subscript 1 end subscript cb (Elimination unimolecular conjugate base) reaction involves the removal of proton by. a conjugate base (step 1) to produce carbanion which loses a leaving group to form an alkene (step 2) and is a slow step.
Isopropyl chloride on heating with concentrated solution of ethanolic KOH gives mainly:

The removal of two atoms or groups, one generally hydrogen open parentheses H to the power of plus end exponent close parentheses and the other a leaving group open parentheses L to the power of minus end exponent close parentheses resulting in the formation of unsaturated compound is known as elimination reaction.

In E subscript 1 end subscript (elimination) reactions, the C minus L bond is broken heterolytic ally (in step 1) to form a carbocation (as in S subscript N to the power of 1 end exponent end subscript reaction) in which open parentheses L to the power of minus end exponent close) is lost (rate determining step). The carbocation (in step 2) loses a proton from the beta-carbon atom by a base (nucleophile) to form an alkene. E subscript 1 end subscript reaction is favoured in compounds in which the leaving group is at secondary open parentheses 2 to the power of ring operator end exponent close parentheses to the power of ´ end exponent or tertiary open parentheses 3 to the power of ring operator end exponent close parentheses position. In E subscript 2 end subscript text end text left parenthesis e l i m i n a t i o n right parenthesis text end text r e a c t i o n s comma text end text t w o text end text s i g m a text end text b o n d s text end text a r e text end text b r o k e n text end text a n d text end text a formed simultaneously. E subscript 2 end subscript reactions occur in one step through a transition state.

E subscript 2 end subscript reactions are most common in haloalkanes (particularly, 1 to the power of ring operator end exponent) and better the leaving group higher is the E subscript 1 end subscript reaction. In E subscript 2 end subscript reactions, both the leaving groups should be antiplanar.
E subscript 1 end subscript cb (Elimination unimolecular conjugate base) reaction involves the removal of proton by. a conjugate base (step 1) to produce carbanion which loses a leaving group to form an alkene (step 2) and is a slow step.
Isopropyl chloride on heating with concentrated solution of ethanolic KOH gives mainly:

Chemistry-General
General
Chemistry-

Karl Ziegler reported that alkenes react with N-bromosuccinimide (NBS) in presence of light to give products resulting from substitution of hydrogen by bromjne at the allylic position, i.e., the position next to the double bond. Let us consider the halogenation of cyclohexene.

Energy level diagram for allylic, vinylic and alkylic, free radicals is .given below:


Above compound on treatment with NBS gives allylic bromides. How many product(s) will be obtained in this reaction?

Karl Ziegler reported that alkenes react with N-bromosuccinimide (NBS) in presence of light to give products resulting from substitution of hydrogen by bromjne at the allylic position, i.e., the position next to the double bond. Let us consider the halogenation of cyclohexene.

Energy level diagram for allylic, vinylic and alkylic, free radicals is .given below:


Above compound on treatment with NBS gives allylic bromides. How many product(s) will be obtained in this reaction?

Chemistry-General
General
Chemistry-

Karl Ziegler reported that alkenes react with N-bromosuccinimide (NBS) in presence of light to give products resulting from substitution of hydrogen by bromjne at the allylic position, i.e., the position next to the double bond. Let us consider the halogenation of cyclohexene.

Energy level diagram for allylic, vinylic and alkylic, free radicals is .given below:

Which of the following sequences is correct about C-H bond energy?

Karl Ziegler reported that alkenes react with N-bromosuccinimide (NBS) in presence of light to give products resulting from substitution of hydrogen by bromjne at the allylic position, i.e., the position next to the double bond. Let us consider the halogenation of cyclohexene.

Energy level diagram for allylic, vinylic and alkylic, free radicals is .given below:

Which of the following sequences is correct about C-H bond energy?

Chemistry-General
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General
Chemistry-

Karl Ziegler reported that alkenes react with N-bromosuccinimide (NBS) in presence of light to give products resulting from substitution of hydrogen by bromjne at the allylic position, i.e., the position next to the double bond. Let us consider the halogenation of cyclohexene.

Energy level diagram for allylic, vinylic and alkylic, free radicals is .given below:

Consider the three types of C-H bonds in cyclohexene.

Which of the following is/are correctly matched?

Karl Ziegler reported that alkenes react with N-bromosuccinimide (NBS) in presence of light to give products resulting from substitution of hydrogen by bromjne at the allylic position, i.e., the position next to the double bond. Let us consider the halogenation of cyclohexene.

Energy level diagram for allylic, vinylic and alkylic, free radicals is .given below:

Consider the three types of C-H bonds in cyclohexene.

Which of the following is/are correctly matched?

Chemistry-General
General
Chemistry-

Karl Ziegler reported that alkenes react with N-bromosuccinimide (NBS) in presence of light to give products resulting from substitution of hydrogen by bromjne at the allylic position, i.e., the position next to the double bond. Let us consider the halogenation of cyclohexene.

Energy level diagram for allylic, vinylic and alkylic, free radicals is .given below:

In the treatment of cyclohexene with NBS, which of the following products will be least stable?

Karl Ziegler reported that alkenes react with N-bromosuccinimide (NBS) in presence of light to give products resulting from substitution of hydrogen by bromjne at the allylic position, i.e., the position next to the double bond. Let us consider the halogenation of cyclohexene.

Energy level diagram for allylic, vinylic and alkylic, free radicals is .given below:

In the treatment of cyclohexene with NBS, which of the following products will be least stable?

Chemistry-General
General
Chemistry-

The high reactivity of alkyl halides can be explained in terms of nature of C-X bond which is highly polarised covalent bond due to large difference in the electronegativities of carbon and halogen .atom. This polarity is responsible for the nucleophilic substitution reactions of alky- halides which mostly occur by S subscript N to the power of 1 end exponent end subscript and S subscript N to the power of 2 end exponent end subscript mechanisms S subscript N to the power of 1 end exponent end subscript reaction is a two step process . and in the first step, R-X ionises to give carbocation (slow process). In the second step, the nucleophile attacks the carbocation from either side to form the product (fast process). In S subscript N to the power of 1 end exponent end subscript reaction, there can be racemization and inversion. S subscript N to the power of 1 end exponent end subscript reaction is favoured by heavy (bulky) groups on the carbon atom attached to halogens. i.e., R subscript 3 end subscript C minus X greater than R subscript 2 end subscript C H minus X greater than R minus C H subscript 2 end subscript X greater than C H subscript 3 end subscript X
In S subscript N to the power of 2 end exponent end subscript reaction, the strong nucleophile OH- attacks from the opposite side of the chlorine atom to give an intermediate (transition state). which breaks to yield the product (alcohol) and leavj.ng open parentheses X to the power of minus end exponent close parentheses group. The alcohol has a configuration opposite to drat 'of the bromide and is said to proceed with inversion of configuration. S subscript N to the power of 2 end exponent end subscript reaction is favoured by small groups on the carbon atom attached to halogen i.e., C H subscript 3 end subscript minus X greater than R minus C H subscript 2 end subscript X greater than R subscript 2 end subscript C H X greater than R subscript 3 end subscript C minus X
The main product formed in the following reaction is:

The high reactivity of alkyl halides can be explained in terms of nature of C-X bond which is highly polarised covalent bond due to large difference in the electronegativities of carbon and halogen .atom. This polarity is responsible for the nucleophilic substitution reactions of alky- halides which mostly occur by S subscript N to the power of 1 end exponent end subscript and S subscript N to the power of 2 end exponent end subscript mechanisms S subscript N to the power of 1 end exponent end subscript reaction is a two step process . and in the first step, R-X ionises to give carbocation (slow process). In the second step, the nucleophile attacks the carbocation from either side to form the product (fast process). In S subscript N to the power of 1 end exponent end subscript reaction, there can be racemization and inversion. S subscript N to the power of 1 end exponent end subscript reaction is favoured by heavy (bulky) groups on the carbon atom attached to halogens. i.e., R subscript 3 end subscript C minus X greater than R subscript 2 end subscript C H minus X greater than R minus C H subscript 2 end subscript X greater than C H subscript 3 end subscript X
In S subscript N to the power of 2 end exponent end subscript reaction, the strong nucleophile OH- attacks from the opposite side of the chlorine atom to give an intermediate (transition state). which breaks to yield the product (alcohol) and leavj.ng open parentheses X to the power of minus end exponent close parentheses group. The alcohol has a configuration opposite to drat 'of the bromide and is said to proceed with inversion of configuration. S subscript N to the power of 2 end exponent end subscript reaction is favoured by small groups on the carbon atom attached to halogen i.e., C H subscript 3 end subscript minus X greater than R minus C H subscript 2 end subscript X greater than R subscript 2 end subscript C H X greater than R subscript 3 end subscript C minus X
The main product formed in the following reaction is:

Chemistry-General
parallel
General
Chemistry-

Compound  undergoes intramolecular nucleophilic substitution of the type .... giving .

Compound  undergoes intramolecular nucleophilic substitution of the type .... giving .

Chemistry-General
General
Chemistry-

In the following compounds, nucleophile and the leaving groups are in the same molecule:
I) 
II) 
III) 
IV) 
These dual nature species can undergo intramolecular and intermolecular nucleophilic substitution. Intramolecular substitution reaction is possible in:

In the following compounds, nucleophile and the leaving groups are in the same molecule:
I) 
II) 
III) 
IV) 
These dual nature species can undergo intramolecular and intermolecular nucleophilic substitution. Intramolecular substitution reaction is possible in:

Chemistry-General
General
Chemistry-

Ullmann reaction is given by:

Ullmann reaction is given by:

Chemistry-General
parallel
General
Chemistry-

The major product of the reaction,
 with HBr is:

The major product of the reaction,
 with HBr is:

Chemistry-General
General
Chemistry-

The reaction given
 is:

The reaction given
 is:

Chemistry-General
General
Chemistry-

In the reaction,

the compound (C) is:

In the reaction,

the compound (C) is:

Chemistry-General
parallel
General
Chemistry-

The major product obtained in the reaction,

The major product obtained in the reaction,

Chemistry-General
General
Chemistry-

In which of the following reactions, an optically. active single product is formed?

In which of the following reactions, an optically. active single product is formed?

Chemistry-General
General
Chemistry-

When  reacts with KOH in presence of water (through S subscript N to the power of 2 end exponent end subscript reaction mechanism) then stereochemistry of product so formed will be:

When  reacts with KOH in presence of water (through S subscript N to the power of 2 end exponent end subscript reaction mechanism) then stereochemistry of product so formed will be:

Chemistry-General
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