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Question

The solubility product of B a S O subscript 4 end subscriptis 1.5 cross times 10 to the power of negative 9 end exponent. The precipitation in a 0.01 M B a to the power of 2 plus end exponent solution will start, on adding H subscript 2 end subscript S O subscript 4 end subscriptof concentration

  1. 10 to the power of negative 9 end exponent blank M  
  2. 10 to the power of negative 8 end exponent blank M  
  3. 10 to the power of negative 7 end exponent blank M  
  4. 10 to the power of negative 6 end exponent blank M  

The correct answer is: 10 to the power of negative 7 end exponent blank M


    K subscript s p end subscript of B a S O subscript 4 end subscript equals 1.5 cross times 10 to the power of negative 9 end exponent colon open square brackets B a to the power of 2 plus end exponent close square brackets equals 0.01 blank M
    open square brackets S O subscript 4 end subscript superscript 2 minus end superscript close square brackets equals fraction numerator 1.5 cross times 10 to the power of negative 9 end exponent over denominator 0.01 end fraction equals 1.5 cross times 10 to the power of negative 7 end exponent

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