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Chemistry-

General

Easy

Question

Which set contains no ionic species?

$N H_{4} C l, O F_{2}, H_{2} S$
$C O_{2}, C C l_{4}, C l_{2}$
$B F_{3}, A l F_{3}, T l F_{3}$
$I_{2}, C a O, C H_{3} C l$

The correct answer is: $C O subscript 2 end subscript comma blank C C l subscript 4 end subscript comma blank C l subscript 2 end subscript$

$N H subscript 4 end subscript C l rightwards harpoon over leftwards harpoon N H subscript 4 end subscript superscript plus end superscript plus C l to the power of minus end exponent$
$A l F subscript 3 end subscript rightwards harpoon over leftwards harpoon A l to the power of 3 plus end exponent plus 3 F to the power of minus end exponent$
$T l F subscript 3 end subscript rightwards harpoon over leftwards harpoon T l to the power of 3 plus end exponent plus 3 F to the power of minus end exponent$
$C a O rightwards harpoon over leftwards harpoon C a to the power of 2 plus end exponent plus O subscript 2 end subscript superscript minus end superscript$
in (a) $N H subscript 4 end subscript C l$ is ionic

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The shape of $I F subscript 7 end subscript$ molecule is

The shape of $I F subscript 7 end subscript$ molecule is

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Solubility of $N a C l comma blank N a subscript 2 end subscript S O subscript 4 end subscript$ and $N a subscript 3 end subscript P O subscript 4 end subscript$ in water in increasing order is

Solubility of $N a C l comma blank N a subscript 2 end subscript S O subscript 4 end subscript$ and $N a subscript 3 end subscript P O subscript 4 end subscript$ in water in increasing order is

Chemistry-General

The nitrogen atoms in $N H subscript 3 end subscript comma blank N H subscript 2 end subscript superscript minus end superscript$ and $N H subscript 4 end subscript superscript plus end superscript$ are all surrounded by eight electrons. When these species are arranged in increasing of $H minus N minus H$ bond angle, correct order is

The nitrogen atoms in $N H subscript 3 end subscript comma blank N H subscript 2 end subscript superscript minus end superscript$ and $N H subscript 4 end subscript superscript plus end superscript$ are all surrounded by eight electrons. When these species are arranged in increasing of $H minus N minus H$ bond angle, correct order is

Chemistry-General

parallel

Consider the following species
I: $S subscript 4 end subscript O subscript 6 end subscript superscript 2 minus end superscript$ ;
II: $S subscript 3 end subscript O subscript 9 end subscript semicolon$
III: $S subscript 2 end subscript O subscript 5 end subscript superscript 2 minus end superscript semicolon$
IV: $P subscript 3 end subscript O subscript 9 end subscript superscript 3 minus end superscript$ Which of the above species have same number of $X minus O minus X$ linkage ( $X equals P$ or S)?

Consider the following species
I: $S subscript 4 end subscript O subscript 6 end subscript superscript 2 minus end superscript$ ;
II: $S subscript 3 end subscript O subscript 9 end subscript semicolon$
III: $S subscript 2 end subscript O subscript 5 end subscript superscript 2 minus end superscript semicolon$
IV: $P subscript 3 end subscript O subscript 9 end subscript superscript 3 minus end superscript$ Which of the above species have same number of $X minus O minus X$ linkage ( $X equals P$ or S)?

Chemistry-General

Which of the following will be most acidic?

Which of the following will be most acidic?

Chemistry-General

The abstraction of proton will be fastest, in which carbon in the following compound,

The abstraction of proton will be fastest, in which carbon in the following compound,

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parallel

Identify the final product (Z) in the following sequence of reactions.

Identify the final product (Z) in the following sequence of reactions.

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Following is hydrated maximum at the position:

Following is hydrated maximum at the position:

Chemistry-General

X and Y are

X and Y are

Chemistry-General

parallel

, is

, is

Chemistry-General

Compound ‘A’ (molecular formula C₃H₈O) is treated with acidified K₂Cr₂O₇ to form a product

Compound ‘A’ (molecular formula C₃H₈O) is treated with acidified K₂Cr₂O₇ to form a product

Chemistry-General

Major product is :

Major product is :

Chemistry-General

parallel

An organic compound C₃H₆O does not give a precipitate with 2, 4 – dinitro phenyl hydrazine and does not react with metallic sodium. It could be

An organic compound C₃H₆O does not give a precipitate with 2, 4 – dinitro phenyl hydrazine and does not react with metallic sodium. It could be

Chemistry-General

Which one of the following reactions cannot be used for the reduction of

Which one of the following reactions cannot be used for the reduction of

Chemistry-General

Chemistry-General

parallel

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