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General

General

Easy

Question

Select the word with Long a and silent e

Lace
Echo
swerd
Debis

The correct answer is: Lace

Lace, Place, Space are some kind of words with long a and silent e

Related Questions to study

If complex numbers z₁,z₂ and z₃ are in AP, then they lie on

If complex numbers z₁,z₂ and z₃ are in AP, then they lie on

Let z,ω be complex numbers such that $z with not stretchy bar on top plus omega with not stretchy bar on top equals 0$ and arg⁡(z m) = π then arg (z)

Let z,ω be complex numbers such that $z with not stretchy bar on top plus omega with not stretchy bar on top equals 0$ and arg⁡(z m) = π then arg (z)

If ω≠1 be a Cube Roots of Unity and (1+ω²)ⁿ= (1+ω⁴)ⁿ, then the least positive value of n is

If ω≠1 be a Cube Roots of Unity and (1+ω²)ⁿ= (1+ω⁴)ⁿ, then the least positive value of n is

parallel

Choose the word that is spelled correctly

Choose the word that is spelled correctly

Select the right words

Select the right words

Choose the synonym of makeshift

Choose the synonym of makeshift

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Choose the synonym of In- between

Choose the synonym of In- between

If the cube roots of unity are 1,w,w², then the roots of the equation (x-1)³+8=0 are

If the cube roots of unity are 1,w,w², then the roots of the equation (x-1)³+8=0 are

If z=x+ i y is a variable complex number such that arg⁡( $open parentheses fraction numerator straight z minus 1 over denominator straight z plus 1 end fraction close parentheses equals straight pi over 4$ then

If z=x+ i y is a variable complex number such that arg⁡( $open parentheses fraction numerator straight z minus 1 over denominator straight z plus 1 end fraction close parentheses equals straight pi over 4$ then

parallel

If z₁,z₂ and z₃,z₄ are two pairs of conjugate complex numbers, then arg $arg invisible function application open parentheses z subscript 1 over z subscript u close parentheses plus arg invisible function application open parentheses z subscript 2 over z subscript 1 close parentheses$

If z₁,z₂ and z₃,z₄ are two pairs of conjugate complex numbers, then arg $arg invisible function application open parentheses z subscript 1 over z subscript u close parentheses plus arg invisible function application open parentheses z subscript 2 over z subscript 1 close parentheses$

If 1,a₁,a₂⋯⋯_n-1 are n roots of unity, then the value of (1-a₁)(1-a₂)(1-a₃)…(1-a_n-1 )

If 1,a₁,a₂⋯⋯_n-1 are n roots of unity, then the value of (1-a₁)(1-a₂)(1-a₃)…(1-a_n-1 )

If Im $open parentheses fraction numerator z minus 1 over denominator 2 z plus 1 end fraction close parentheses equals negative 4$ then locus of z is

If Im $open parentheses fraction numerator z minus 1 over denominator 2 z plus 1 end fraction close parentheses equals negative 4$ then locus of z is

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If z²+z+1=0 where z is a complex number, then value of $open parentheses z plus 1 over z close parentheses squared plus open parentheses z squared plus 1 over z squared close parentheses squared plus open parentheses z cubed plus 1 over z cubed close parentheses squared plus midline horizontal ellipsis times times plus open parentheses z to the power of 6 plus 1 over z to the power of 6 close parentheses squared$ is [ ]

If z²+z+1=0 where z is a complex number, then value of $open parentheses z plus 1 over z close parentheses squared plus open parentheses z squared plus 1 over z squared close parentheses squared plus open parentheses z cubed plus 1 over z cubed close parentheses squared plus midline horizontal ellipsis times times plus open parentheses z to the power of 6 plus 1 over z to the power of 6 close parentheses squared$ is [ ]

Choose the synonym of tale

Choose the synonym of tale

If a=Cis⁡ α,b=Cis⁡ β c=Cis γ and $fraction numerator left parenthesis b plus c right parenthesis left parenthesis c plus a right parenthesis left parenthesis a plus b right parenthesis over denominator a b c end fraction equals$
$K cos invisible function application open parentheses fraction numerator alpha minus beta over denominator 2 end fraction close parentheses cos invisible function application open parentheses fraction numerator beta minus gamma over denominator 2 end fraction close parentheses cos invisible function application open parentheses fraction numerator gamma minus alpha over denominator 2 end fraction close parentheses$ then K= (H.W)

If a=Cis⁡ α,b=Cis⁡ β c=Cis γ and $fraction numerator left parenthesis b plus c right parenthesis left parenthesis c plus a right parenthesis left parenthesis a plus b right parenthesis over denominator a b c end fraction equals$
$K cos invisible function application open parentheses fraction numerator alpha minus beta over denominator 2 end fraction close parentheses cos invisible function application open parentheses fraction numerator beta minus gamma over denominator 2 end fraction close parentheses cos invisible function application open parentheses fraction numerator gamma minus alpha over denominator 2 end fraction close parentheses$ then K= (H.W)

parallel

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