Question
A man born in the first half of the nineteenth century was x years old in the year x2. He was born?
- 1806
- 1812
- 1825
- 1836
Hint:
The only perfect square between 1800 and 1850 is 1849 (432).
The correct answer is: 1806
GIVEN-
The man was born between 1800 and 1850.
In the year x2, his age was x.
TO FIND-
Year in which the man was born.
SOLUTION-
We know that the only perfect square between 1800 and 1850 is 1849 i.e. (432).
And we know that in the year x2, his age is x.
So, the man was 43 (x) years old in 1849 (x2).
Thus, he was born in the year = (1849 − 43) = 1806
FINAL ANSWER-
Option 'a' i.e. '1806' is the correct answer to the given question.
Option 'a' i.e. '1806' is the correct answer to the given question.
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