Question
Complete the multiplication sentence.
3 × ? = 
.
Hint:
In the question, given 
. It is required to find the number in place of the question mark. To find that number we just need to divide by 3. Since we all know that if a number multiplied by 3 gives then the number is equal to divided by 3.
The correct answer is:
Step by step solution:
Given,
Let us consider the number required to be found as 'x'.
Now, the equation becomes 
Now, we all know that in fraction division, we can simply reciprocate the number to the right of the '
' sign and replace the '' sign with 'x' sign and perform multiplication.
Therefore, 
Here, the 3 in the numerator of the first fraction gets reduced by the 3 in the denominator of the second fraction.
Thus, we get x = which is the required answer.
Hence, option (d) is the correct option.
Related Questions to study
Choose the correct answer.
Also, consider the multiplication sentence.
2 × ? = 
.
Choose the correct answer.
Also, consider the multiplication sentence.
2 × ? = .
Two-thirds of the students in your class are boys. One-eighth of the boys play soccer. The fraction of the number of boys in your class who play soccer is.
The fractions can also be simplified before multiplying by factoring out common factors in the numerator and denominator.
Two-thirds of the students in your class are boys. One-eighth of the boys play soccer. The fraction of the number of boys in your class who play soccer is.
The fractions can also be simplified before multiplying by factoring out common factors in the numerator and denominator.
Name the operation you would use.
The bleachers at a football game are 
full, and 
of the fans in the bleachers are rooting for the home team. Select the fraction of the bleachers filled with home-team fans.
The fractions can also be simplified before multiplying by factoring out common factors in the numerator and denominator.
Name the operation you would use.
The bleachers at a football game are full, and of the fans in the bleachers are rooting for the home team. Select the fraction of the bleachers filled with home-team fans.
The fractions can also be simplified before multiplying by factoring out common factors in the numerator and denominator.
=
=
A team of runners is needed to run a 
-mile relay race. If each runner must run 
mile. Find the number of runners they need to run the race.
The fractions can also be simplified before multiplying by factoring out common factors in the numerator and denominator.
A team of runners is needed to run a -mile relay race. If each runner must run mile. Find the number of runners they need to run the race.
The fractions can also be simplified before multiplying by factoring out common factors in the numerator and denominator.
Multiply 
.
The fractions can also be simplified before multiplying by factoring out common factors in the numerator and denominator.
Multiply .
The fractions can also be simplified before multiplying by factoring out common factors in the numerator and denominator.
Simplify 
=
The fractions can also be simplified before multiplying by factoring out common factors in the numerator and denominator.
Simplify =
The fractions can also be simplified before multiplying by factoring out common factors in the numerator and denominator.
Simplify 
The fractions can also be simplified before multiplying by factoring out common factors in the numerator and denominator.
Simplify
The fractions can also be simplified before multiplying by factoring out common factors in the numerator and denominator.
Simplify 
The fractions can also be simplified before multiplying by factoring out common factors in the numerator and denominator.
Simplify
The fractions can also be simplified before multiplying by factoring out common factors in the numerator and denominator.
Simplify 
The factions can also be simplified first before multiplying by factoring out common factors in the numerator and the denominator.
Simplify
The factions can also be simplified first before multiplying by factoring out common factors in the numerator and the denominator.
=
Another approach to the question could be that first we can cut both the 3s, i.e., the 3 in the numerator of the first fraction and the 3 in the denominator of the second fraction. Also, we can reduce the 8 in the denominator of the first fraction and the 2 in the numerator in the second fraction. The 8 gets reduced to 4.
Hence, 
Thus, option (a) is the correct option.
=
Another approach to the question could be that first we can cut both the 3s, i.e., the 3 in the numerator of the first fraction and the 3 in the denominator of the second fraction. Also, we can reduce the 8 in the denominator of the first fraction and the 2 in the numerator in the second fraction. The 8 gets reduced to 4.
Hence,
Thus, option (a) is the correct option.
=
In the question, another approach could be that we can cut the 2 in the denominator of the first fraction by the 4 in the numerator of the second fraction and reduce the 4 to 2. Then, we get 
Thus, we get option (c) as the correct option.
=
In the question, another approach could be that we can cut the 2 in the denominator of the first fraction by the 4 in the numerator of the second fraction and reduce the 4 to 2. Then, we get
Thus, we get option (c) as the correct option.
George has 
pan of brownies. He eats of them. The fraction of brownies George ate. is
George has pan of brownies. He eats of them. The fraction of brownies George ate. is
Multiply .
In the question, another approach could be that we can reduce the first fraction 
Then we get, 
. Here, the 3 in the denominator of the first fraction gets cut by the 3 in the numerator of the second fraction. Hence, we get the product as 
.
Thus, we get option (a) as the correct option.
Multiply .
In the question, another approach could be that we can reduce the first fraction
Then we get, . Here, the 3 in the denominator of the first fraction gets cut by the 3 in the numerator of the second fraction. Hence, we get the product as .
Thus, we get option (a) as the correct option.
Multiply 
.
In the question, another approach could be that we can reduce 
into by dividing both the numerator and denominator by 2 which is the HCF of both the numerator and the denominator. Then we simply get 
Thus, the correct option is option (a)
Multiply .
In the question, another approach could be that we can reduce into by dividing both the numerator and denominator by 2 which is the HCF of both the numerator and the denominator. Then we simply get
Thus, the correct option is option (a)
