Question
Find the sum of measures of interior angles of a nonagon.
- 1080o
- 1260o
- 540o
- 720o
Hint:
Sum of internal angles of a polygon =( n-2) x 180
The correct answer is: 1260o
1260
In a nonagon , number of sides n = 9
Sum of internal angles of a polygon =( n-2) x 180
= (9-2) x 180
= 7 x 180
= 1260 degrees
Sum of internal angles = (n-2) x 180
the sum of external angles of a polygon =360
these are properties of polygons.
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