Question
Find the area of a kite with diagonal lengths of a + b and 2a − 2b.
- 2a2 - 2b2
- a2 -ab - b2
- a2 - b2
- a2 + b2
Hint:
Area of kite = ½ x product of diagonals
The correct answer is: a2 - b2
½ x (a+b ) x (2a-2b) = ½ (2a2 – 2b2 )
= a2 – b2
a kite is a polygon with 2 pairs of sides which are equal in length with the equal sides adjacent to each other.
Related Questions to study
Two congruent equilateral triangles with sides of length 1 are connected so that they share a side. Each triangle has a height of h. Express the area of the shape in terms of h.
the above stated problem can be better understood with this picture.
Two congruent equilateral triangles with sides of length 1 are connected so that they share a side. Each triangle has a height of h. Express the area of the shape in terms of h.
the above stated problem can be better understood with this picture.
Which of the following shapes is a kite?
According to definition. A kite is a quadrilateral with 2 pairs of equal length sides, which are adjacent to each other.it diagonals intersect at right angles.
Which of the following shapes is a kite?
According to definition. A kite is a quadrilateral with 2 pairs of equal length sides, which are adjacent to each other.it diagonals intersect at right angles.
A trapezoid has a base of length 4, another base of length s, and a height of length s. A square has sides of length s. What is the value of s such that the area of the trapezoid and the area of the square are equal?
Area of the given polygons:
Area of square = s*s = s2
Area of a trapezoid = ½ x sum of parallel sides x distance between them
A trapezoid has a base of length 4, another base of length s, and a height of length s. A square has sides of length s. What is the value of s such that the area of the trapezoid and the area of the square are equal?
Area of the given polygons:
Area of square = s*s = s2
Area of a trapezoid = ½ x sum of parallel sides x distance between them