Mathematics
Grade9
Easy

Question

Find the surface area of the figure. Round your answer to the nearest hundredth.

  1. 89.4 yd squared
  2. 163.20 yd squared
  3. 44.7 yd squared
  4. 64.8 yd squared

hintHint:

The surface area of Pyramid = B space plus space 1 half space cross times space P l space where p is the perimeter of the base , B is area of the base and l is the slant height of the pyramid.

The correct answer is: 89.4 yd squared


    Given the base of the triangular pyramid is equilateral triangle with side length 6 yd and slant height of pyramid is 8.2 yd
    text  The perimeter of base = 3 x 6 = 18 yd end text
text The area of the base is  end text 1 divided by 2 cross times 6 cross times 5.2 equals 15.6 space yd squared
U s e space t h e space s u r f a c e space a r e a space f o r m u l a comma space
text  Surface area  end text equals straight B plus 1 half cross times Pl
S. A space equals space 15.6 space plus space 1 half space left parenthesis 18 right parenthesis left parenthesis 8.2 right parenthesis space equals space 15.6 space plus 73.8
equals 89.4 space yd squared
    Therefore, surface area of the given figure is 89.4 yd squared.

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