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Mathematics

Grade-7

Easy

Question

If $straight g space cross times space fraction numerator negative 1 over denominator 2 end fraction space equals space fraction numerator negative 13 over denominator 4 end fraction$ , then value of g = _____.

$\frac{2}{13}$
$\frac{13}{2}$
$\frac{4}{9}$
$\frac{9}{4}$

hint Hint:

Use the simple division method to find the value of g.

The correct answer is: $13 over 2$

STEP BY STEP SOLUTION
$g space cross times space fraction numerator negative 1 over denominator 2 end fraction space equals space fraction numerator negative 13 over denominator 4 end fraction T o space f i n d space t h e space v a l u e space o f space g space w e space w i l l space d i v i d e space fraction numerator negative 13 over denominator 4 end fraction space b y space fraction numerator negative 1 over denominator 2 end fraction g space equals space fraction numerator negative 13 over denominator 4 end fraction space divided by space fraction numerator negative 1 over denominator 2 end fraction g space equals space fraction numerator negative 13 over denominator 4 end fraction space cross times fraction numerator negative 2 over denominator 1 end fraction g space equals space 26 over 4 g space equals space 13 over 2$

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