Mathematics
Grade-8
Easy

Question

In which triangle all three sides are of equal measure?

  1. Scalene triangle
  2. Right isosceles triangle
  3. Equilateral triangle
  4. Isosceles triangle

hintHint:

We recall the definitions of side and vertex of a polygon. We recall the definition of length of a side
triangle and then recall the definitions of scalene, isosceles, equilateral triangles based on relationship
among the three sides of a triangle. We draw the figure of triangle ABC for scalene, isosceles,
equilateral conditions on sides. We find that equilateral has three sides with equal length which
means AB=BC=AC of a triangle ABC

The correct answer is: Equilateral triangle


    an equilateral triangle is a triangle in which all three sides have the same length. an equilateral triangle is
    also equiangular; that is, all three internal angles are also congruent to each other and are each 60°.

    Related Questions to study

    Grade-8
    Mathematics

    Find the vertices of each of the figures of rotation 900 counter-clockwise about the origin

    Given Data:

    >>From figure, the vertices of the triangle are:
    B(-5,0) and E(-2,1) and G(-2, -3).
    >>>let, the point (x, y) be in the space and the Angle of Rotation becomes alpha= 90.
    >>>new coordinates are:
     (x cosalpha - y sinalpha , y cosalpha + x sinalpha)
    = (x cos90 -y sin90 , y cos90 + x sin90)
    = (-y, x).
    * Hence, the final coordinates after rotation through 90 degrees counter clockwise are (-y, x).
    >>>Similarly, for the coordinates B(-5,0) and E(-2,1) and G(-2, -3) the rotation of points through 90 degrees counter clock wise becomes:
    B(0,-5) and E(3, -2) and G(3,2).
    ***Therefore, the coordinates of triangle B(-5,0) and E(-2,1) and G(-2, -3) after rotation through 90 degrees counter clockwise becomes  B(0,-5) and E(3, -2) and G(3,2).

    Find the vertices of each of the figures of rotation 900 counter-clockwise about the origin

    MathematicsGrade-8

    Given Data:

    >>From figure, the vertices of the triangle are:
    B(-5,0) and E(-2,1) and G(-2, -3).
    >>>let, the point (x, y) be in the space and the Angle of Rotation becomes alpha= 90.
    >>>new coordinates are:
     (x cosalpha - y sinalpha , y cosalpha + x sinalpha)
    = (x cos90 -y sin90 , y cos90 + x sin90)
    = (-y, x).
    * Hence, the final coordinates after rotation through 90 degrees counter clockwise are (-y, x).
    >>>Similarly, for the coordinates B(-5,0) and E(-2,1) and G(-2, -3) the rotation of points through 90 degrees counter clock wise becomes:
    B(0,-5) and E(3, -2) and G(3,2).
    ***Therefore, the coordinates of triangle B(-5,0) and E(-2,1) and G(-2, -3) after rotation through 90 degrees counter clockwise becomes  B(0,-5) and E(3, -2) and G(3,2).

    Grade-8
    Mathematics

    Find the vertices of each of the figure of rotation 900 clockwise about the origin

    Given Data:
                          
    * From figure, the points are K(2, -2) and U(3, 3) and T(5, 0) are the vertices of the triangle.
    >>Let (x, y) be the point in the space and angle of rotation becomes alpha= -90 degrees.
    *Then, the new coordinates are :
    (x cosalpha - y sinalpha , y cosalpha + x sinalpha)
                      = (x cos(-90) -y sin(-90) , y cos(-90) + x sin(-90))
                      = (y, -x).
    >>Then, the new coordinates are (y, -x).
    >>>Similarly, the rotation of triangular vertices K(2, -2) and U(3, 3) and T(5, 0) through 90 degrees clockwise becomes :
                                      K(-2, -2) and U(3, -3) and T(0, -5).
    *Therefore, the vertices K(2, -2) and U(3, 3) and T(5, 0) after rotation through 90 degrees clockwise becomes  K(-2, -2) and U(3, -3) and T(0, -5).

    Find the vertices of each of the figure of rotation 900 clockwise about the origin

    MathematicsGrade-8

    Given Data:
                          
    * From figure, the points are K(2, -2) and U(3, 3) and T(5, 0) are the vertices of the triangle.
    >>Let (x, y) be the point in the space and angle of rotation becomes alpha= -90 degrees.
    *Then, the new coordinates are :
    (x cosalpha - y sinalpha , y cosalpha + x sinalpha)
                      = (x cos(-90) -y sin(-90) , y cos(-90) + x sin(-90))
                      = (y, -x).
    >>Then, the new coordinates are (y, -x).
    >>>Similarly, the rotation of triangular vertices K(2, -2) and U(3, 3) and T(5, 0) through 90 degrees clockwise becomes :
                                      K(-2, -2) and U(3, -3) and T(0, -5).
    *Therefore, the vertices K(2, -2) and U(3, 3) and T(5, 0) after rotation through 90 degrees clockwise becomes  K(-2, -2) and U(3, -3) and T(0, -5).

    Grade-8
    Mathematics

    Find the vertices of each of the figure of rotation 1800 about the origin

    Given Data:

    >>From figure, the coordinates of the points w, u, x are.
    >>> W(-4, -3) and U(4, 0) and X(-3, -2) are the required coordinates of a triangle.
    >>Let, (x, y) be the point in the space and are rotated through 180 degrees.
    Then, the new coordinates are:
     (x cosalpha - y sinalpha , y cosalpha + x sinalpha)
    = (x cos180 -y sin180 , y cos180 + xsin180)
    = (-x , -y)
    * Then, the new coordinates of (x, y) after rotation through 180 degrees is (-x, -y).
    >>>Similarly, for  W(-4, -3) and U(4, 0) and X(-3, -2) the new coordinates are:
    W(4, 3) and U(-4, 0) and (3, 2).
    >>>Hence, the rotation of points W(-4, -3) and U(4, 0) and X(-3, -2) through 180 degrees becomes  W(4, 3) and U(-4, 0) and (3, 2).

    Find the vertices of each of the figure of rotation 1800 about the origin

    MathematicsGrade-8

    Given Data:

    >>From figure, the coordinates of the points w, u, x are.
    >>> W(-4, -3) and U(4, 0) and X(-3, -2) are the required coordinates of a triangle.
    >>Let, (x, y) be the point in the space and are rotated through 180 degrees.
    Then, the new coordinates are:
     (x cosalpha - y sinalpha , y cosalpha + x sinalpha)
    = (x cos180 -y sin180 , y cos180 + xsin180)
    = (-x , -y)
    * Then, the new coordinates of (x, y) after rotation through 180 degrees is (-x, -y).
    >>>Similarly, for  W(-4, -3) and U(4, 0) and X(-3, -2) the new coordinates are:
    W(4, 3) and U(-4, 0) and (3, 2).
    >>>Hence, the rotation of points W(-4, -3) and U(4, 0) and X(-3, -2) through 180 degrees becomes  W(4, 3) and U(-4, 0) and (3, 2).

    parallel
    Grade-8
    Mathematics

    What will be the coordinates of the image of ABC with points A (-3,4) B (0, 1), C (-5, 2) after it is rotated 90o counter-clockwise about the origin?

    Given That:
                        A (-3,4) B (0, 1), C (-5, 2) are the vertices of a triangle.
    >>>The vertices of a triangle are rotated through 90 degrees counter clockwise direction.
    >>>Let, the point on the space be (x, y). Then Angle of Rotation alpha becomes 90 degrees.
    >>>Hence, new coordinates are:
                                     = (x cosalpha - y sinalpha , y cosalpha + x sinalpha)
                                     = (x cos90 - y sin90 , y cos90 + x sin90)
                                     = (-y , x).
    >>>Similarly, the rotation of the points  A (-3,4) B (0, 1), C (-5, 2)  becomes:
                    A(-4,-3) and B(-1,0) and C(-2, -5).
    ***Therefore, the triangle vertices A (-3,4) B (0, 1), C (-5, 2)  after rotation through 90 degrees counter clockwise are   A(-4,-3) and B(-1,0) and C(-2, -5).

    What will be the coordinates of the image of ABC with points A (-3,4) B (0, 1), C (-5, 2) after it is rotated 90o counter-clockwise about the origin?

    MathematicsGrade-8

    Given That:
                        A (-3,4) B (0, 1), C (-5, 2) are the vertices of a triangle.
    >>>The vertices of a triangle are rotated through 90 degrees counter clockwise direction.
    >>>Let, the point on the space be (x, y). Then Angle of Rotation alpha becomes 90 degrees.
    >>>Hence, new coordinates are:
                                     = (x cosalpha - y sinalpha , y cosalpha + x sinalpha)
                                     = (x cos90 - y sin90 , y cos90 + x sin90)
                                     = (-y , x).
    >>>Similarly, the rotation of the points  A (-3,4) B (0, 1), C (-5, 2)  becomes:
                    A(-4,-3) and B(-1,0) and C(-2, -5).
    ***Therefore, the triangle vertices A (-3,4) B (0, 1), C (-5, 2)  after rotation through 90 degrees counter clockwise are   A(-4,-3) and B(-1,0) and C(-2, -5).

    Grade-8
    Mathematics

    What will be the coordinates of the image of ABC with points A (-3,4) B (0, 1), C (-5, 2) after it is rotated 180o about the origin?

    Given That:
                      A (-3,4), B(0, 1), C (-5, 2) are the points of triangle.
    >>we re asked to rotate the vertices of triangle by 180 degrees.
    >>>let, the point be (x, y) then the angle of rotation be 180 degrees. Then:
    >>New Coordinates are:
    (x cosalpha - y sinalpha , y cosalpha + x sinalpha).
                                 = (x cos180 - y sin180 , y cos180 + x sin180)
                                 = (-x , -y).
    >>>Hence, any point that rotated by 180 degrees will just change the sign of the coordinates.
    >>>Similarly, for triangle coordinates  A (-3,4), B(0, 1), C (-5, 2) the rotation through 180 degrees about origin becomes : A(3, -4) and B(0, -1) and C(5, -2).

    What will be the coordinates of the image of ABC with points A (-3,4) B (0, 1), C (-5, 2) after it is rotated 180o about the origin?

    MathematicsGrade-8

    Given That:
                      A (-3,4), B(0, 1), C (-5, 2) are the points of triangle.
    >>we re asked to rotate the vertices of triangle by 180 degrees.
    >>>let, the point be (x, y) then the angle of rotation be 180 degrees. Then:
    >>New Coordinates are:
    (x cosalpha - y sinalpha , y cosalpha + x sinalpha).
                                 = (x cos180 - y sin180 , y cos180 + x sin180)
                                 = (-x , -y).
    >>>Hence, any point that rotated by 180 degrees will just change the sign of the coordinates.
    >>>Similarly, for triangle coordinates  A (-3,4), B(0, 1), C (-5, 2) the rotation through 180 degrees about origin becomes : A(3, -4) and B(0, -1) and C(5, -2).

    Grade-8
    Mathematics

    In what quadrant will an image be if the figure is in quadrant I and is rotated 90° counter clockwise?



    * In Mathematics, rotation means the Circular movement of an object around one fixed point.

    * In rotation, the image after transformation remains constant.

    * Hence, it is called as a rigid transformation.

    * No Change in shape and size.

    * The Shape rotates counter- clockwise when the degrees is positive and rotates clockwise when degrees is negative.

    *The Rotation of a point (x, y) about origin and through angle alpha, then:
    New coordinates of a point (x, y) after it's rotation becomes (x cosalpha - y sinalpha , y cosalpha + x sinalpha).
     

    In what quadrant will an image be if the figure is in quadrant I and is rotated 90° counter clockwise?

    MathematicsGrade-8



    * In Mathematics, rotation means the Circular movement of an object around one fixed point.

    * In rotation, the image after transformation remains constant.

    * Hence, it is called as a rigid transformation.

    * No Change in shape and size.

    * The Shape rotates counter- clockwise when the degrees is positive and rotates clockwise when degrees is negative.

    *The Rotation of a point (x, y) about origin and through angle alpha, then:
    New coordinates of a point (x, y) after it's rotation becomes (x cosalpha - y sinalpha , y cosalpha + x sinalpha).
     

    parallel
    Grade-8
    Mathematics

    In what quadrant will an image be if the figure is in quadrant II and is rotated 180° clockwise?


    * In Mathematics, rotation means the Circular movement of an object around one fixed point.

    * In rotation, the image after transformation remains constant.

    * Hence, it is called as a rigid transformation.

    * No Change in shape and size.

    * The Shape rotates counter- clockwise when the degrees is positive and rotates clockwise when degrees is negative.

    *The Rotation of a point (x, y) about origin and through angle alpha, then:
    New coordinates of a point (x, y) after it's rotation becomes (x cosalpha - y sinalpha , y cosalpha + x sinalpha).

     

    In what quadrant will an image be if the figure is in quadrant II and is rotated 180° clockwise?

    MathematicsGrade-8


    * In Mathematics, rotation means the Circular movement of an object around one fixed point.

    * In rotation, the image after transformation remains constant.

    * Hence, it is called as a rigid transformation.

    * No Change in shape and size.

    * The Shape rotates counter- clockwise when the degrees is positive and rotates clockwise when degrees is negative.

    *The Rotation of a point (x, y) about origin and through angle alpha, then:
    New coordinates of a point (x, y) after it's rotation becomes (x cosalpha - y sinalpha , y cosalpha + x sinalpha).

     

    Grade-8
    Mathematics

    In what quadrant will an image be if the figure is in quadrant III and is rotated 90° clockwise?


    * In Mathematics, rotation means the Circular movement of an object around one fixed point.

    * In rotation, the image after transformation remains constant.

    * Hence, it is called as a rigid transformation.

    * No Change in shape and size.

    * The Shape rotates counter- clockwise when the degrees is positive and rotates clockwise when degrees is negative.

    *The Rotation of a point (x, y) about origin and through angle alpha, then:
    New coordinates of a point (x, y) after it's rotation becomes (x cosalpha - y sinalpha , y cosalpha + x sinalpha).

     

    In what quadrant will an image be if the figure is in quadrant III and is rotated 90° clockwise?

    MathematicsGrade-8


    * In Mathematics, rotation means the Circular movement of an object around one fixed point.

    * In rotation, the image after transformation remains constant.

    * Hence, it is called as a rigid transformation.

    * No Change in shape and size.

    * The Shape rotates counter- clockwise when the degrees is positive and rotates clockwise when degrees is negative.

    *The Rotation of a point (x, y) about origin and through angle alpha, then:
    New coordinates of a point (x, y) after it's rotation becomes (x cosalpha - y sinalpha , y cosalpha + x sinalpha).

     

    Grade-8
    Mathematics

    If the point (-4, -6) rotates 180° counter-clockwise, then the point will be

    Given Data:
    If the point (-4, -6) rotates 180° counter-clockwise, then the point will be
    >>>Since it is counter clockwise the angle of rotation becomes alpha= 180 degrees.
    >>Point (x, y) = (-4, -6)
    >>>New Coordinates are:
    (x cosalpha - y sinalpha , y cosalpha + x sinalpha).
    = (-4cos180 + 6sin180 , -6cos180 -6sin180)
    = (4 , 6).
    ***Therefore, the rotation of the point (-4, -6 ) through 180 degrees counter clockwise becomes (4, 6).

    If the point (-4, -6) rotates 180° counter-clockwise, then the point will be

    MathematicsGrade-8

    Given Data:
    If the point (-4, -6) rotates 180° counter-clockwise, then the point will be
    >>>Since it is counter clockwise the angle of rotation becomes alpha= 180 degrees.
    >>Point (x, y) = (-4, -6)
    >>>New Coordinates are:
    (x cosalpha - y sinalpha , y cosalpha + x sinalpha).
    = (-4cos180 + 6sin180 , -6cos180 -6sin180)
    = (4 , 6).
    ***Therefore, the rotation of the point (-4, -6 ) through 180 degrees counter clockwise becomes (4, 6).

    parallel
    Grade-8
    Mathematics

    If the point (4, 6) rotates 90° counter-clockwise, then the point will be

    Given Data:
    If the point (4, 6) rotates 90° counter-clockwise, then the point will be
    >>>Since, it is counter clockwise rotation angle of rotation becomes alpha= 90 degrees.
    >>point (x, y)= (4, 6)
    *New Coordinates are:
    (x cosalpha - y sinalpha , y cosalpha + x sinalpha).
    = (4cos90 - 6sin90 , 6cos90 + 4sin90)
    = (-6 , 4).
    ***The rotation of the point (4, 6 ) through 90 degrees counter clockwise becomes (-6, 4).

    If the point (4, 6) rotates 90° counter-clockwise, then the point will be

    MathematicsGrade-8

    Given Data:
    If the point (4, 6) rotates 90° counter-clockwise, then the point will be
    >>>Since, it is counter clockwise rotation angle of rotation becomes alpha= 90 degrees.
    >>point (x, y)= (4, 6)
    *New Coordinates are:
    (x cosalpha - y sinalpha , y cosalpha + x sinalpha).
    = (4cos90 - 6sin90 , 6cos90 + 4sin90)
    = (-6 , 4).
    ***The rotation of the point (4, 6 ) through 90 degrees counter clockwise becomes (-6, 4).

    Grade-8
    Mathematics

    If the point (2, 3) rotates 90°clockwise, then the point will be

    Given data:
    If the point (2, 3) rotates 90°clockwise, then the point will be
    >>>Since, it is clockwise rotation angle of rotation alpha becomes negative that is  alpha= -90.
    >>And the point (x, y) = (2, 3).
    >>>Hence, the new coordinates are:
    (x cosalpha - y sinalpha , y cosalpha + x sinalpha).
                                 = (2 cos(-90) - 3 sin(-90) , 3 cos(-90) + 2 sin(-90))
                                 = (3 ,-2).
    **Hence, the rotation of the point (2, 3) through 90 degrees clockwise is (3, -2).

    If the point (2, 3) rotates 90°clockwise, then the point will be

    MathematicsGrade-8

    Given data:
    If the point (2, 3) rotates 90°clockwise, then the point will be
    >>>Since, it is clockwise rotation angle of rotation alpha becomes negative that is  alpha= -90.
    >>And the point (x, y) = (2, 3).
    >>>Hence, the new coordinates are:
    (x cosalpha - y sinalpha , y cosalpha + x sinalpha).
                                 = (2 cos(-90) - 3 sin(-90) , 3 cos(-90) + 2 sin(-90))
                                 = (3 ,-2).
    **Hence, the rotation of the point (2, 3) through 90 degrees clockwise is (3, -2).

    Grade-8
    Mathematics

    In rotation, the point (x, y) after moving 180° both clockwise and anti-clockwise will be

    Given Data:
                        In rotation, the point (x, y) after moving 180° both clockwise and anti-clockwise will be
    >>First step is to rotate the point (x, y) through 180 degrees clockwise.
    * Hence, the angle of rotation becomes alpha= -180
    The new coordinates are:
                                    = (x cosalpha - y sinalpha , y cosalpha + x sinalpha)
                                    = (x cos(-180) - y sin(-180) , y cos(-180) + x sin(-180))
                                    = (-x, -y).
    ***Therefore, the rotation of a point (x, y) through 180 degrees clockwise gives (-x, -y).
    >>>similarly, the rotation of the point (x, y) through 180 degrees counter clockwise gives:
    *The new Coordinates are:
                  =  (x cosalpha - y sinalpha , y cosalpha + x sinalpha)

                  = (x cos(180) -y sin(180) , y cos(180) + x sin(180))
                  = (-x , -y).
    ***Therefore, the rotation of the point (x, y) through 180 degrees counter clockwise gives (-x, -y)
    >>>Hence, we can say that the rotation of the point (x, y) through any direction yields (-x, -y).

    In rotation, the point (x, y) after moving 180° both clockwise and anti-clockwise will be

    MathematicsGrade-8

    Given Data:
                        In rotation, the point (x, y) after moving 180° both clockwise and anti-clockwise will be
    >>First step is to rotate the point (x, y) through 180 degrees clockwise.
    * Hence, the angle of rotation becomes alpha= -180
    The new coordinates are:
                                    = (x cosalpha - y sinalpha , y cosalpha + x sinalpha)
                                    = (x cos(-180) - y sin(-180) , y cos(-180) + x sin(-180))
                                    = (-x, -y).
    ***Therefore, the rotation of a point (x, y) through 180 degrees clockwise gives (-x, -y).
    >>>similarly, the rotation of the point (x, y) through 180 degrees counter clockwise gives:
    *The new Coordinates are:
                  =  (x cosalpha - y sinalpha , y cosalpha + x sinalpha)

                  = (x cos(180) -y sin(180) , y cos(180) + x sin(180))
                  = (-x , -y).
    ***Therefore, the rotation of the point (x, y) through 180 degrees counter clockwise gives (-x, -y)
    >>>Hence, we can say that the rotation of the point (x, y) through any direction yields (-x, -y).

    parallel
    Grade-8
    Mathematics

    In rotation, the point (x, y) after moving 270° clockwise and 90° counter-clockwise will be

    Given Data:
    In rotation, the point (x, y) after moving 270° clockwise and 90° counter-clockwise will be
    >>>The first step is to rotate a point (x, y) through 270 degrees clockwise
    * Angle of rotation alpha becomes -270
    * Then, the coordinates after rotation :
                          = (x cosalpha - y sinalpha , y cosalpha + x sinalpha)
                          = (x cos(-270) - y sin(-270) , y cos(-270) + x sin(-270))
                          = (-y, x).
    >>>Second step is to rotate (-y, x) through 90 degrees counter clockwise 
    * Angle of rotation alpha becomes 90 degrees.
    * Then , the new coordinates after rotation becomes:
                                 =  (x cosalpha - y sinalpha , y cosalpha + x sinalpha)

                                 = (-y cos(90) - x sin(90) , x cos(90) -y sin(90))
                                 = (-x , -y).
    ***Therefore the rotation of a point (x, y) through 270 degrees clockwise and 90 degrees counter clockwise becomes (-x, -y).

    In rotation, the point (x, y) after moving 270° clockwise and 90° counter-clockwise will be

    MathematicsGrade-8

    Given Data:
    In rotation, the point (x, y) after moving 270° clockwise and 90° counter-clockwise will be
    >>>The first step is to rotate a point (x, y) through 270 degrees clockwise
    * Angle of rotation alpha becomes -270
    * Then, the coordinates after rotation :
                          = (x cosalpha - y sinalpha , y cosalpha + x sinalpha)
                          = (x cos(-270) - y sin(-270) , y cos(-270) + x sin(-270))
                          = (-y, x).
    >>>Second step is to rotate (-y, x) through 90 degrees counter clockwise 
    * Angle of rotation alpha becomes 90 degrees.
    * Then , the new coordinates after rotation becomes:
                                 =  (x cosalpha - y sinalpha , y cosalpha + x sinalpha)

                                 = (-y cos(90) - x sin(90) , x cos(90) -y sin(90))
                                 = (-x , -y).
    ***Therefore the rotation of a point (x, y) through 270 degrees clockwise and 90 degrees counter clockwise becomes (-x, -y).

    Grade-8
    Mathematics

    In rotation, the point (x, y) after moving 270° clockwise will be

    Given Data:
                          In rotation, the point (x, y) after moving 270° clockwise will be
    >>>since, it is clockwise rotation the angle of rotation alpha becomes negative.
    >>alpha= -270.
    >>>New coordinates of a point after rotation:
                                 = (x cosalpha - y sinalpha , y cosalpha + x sinalpha)
    = (x cos(-270) - y sin(-270) , y sin(-270) + x sin(-270))
    = (-y , x).
    ***Hence, the rotation of the point (x, y) through 270 degrees clockwise becomes (-y, x)

    In rotation, the point (x, y) after moving 270° clockwise will be

    MathematicsGrade-8

    Given Data:
                          In rotation, the point (x, y) after moving 270° clockwise will be
    >>>since, it is clockwise rotation the angle of rotation alpha becomes negative.
    >>alpha= -270.
    >>>New coordinates of a point after rotation:
                                 = (x cosalpha - y sinalpha , y cosalpha + x sinalpha)
    = (x cos(-270) - y sin(-270) , y sin(-270) + x sin(-270))
    = (-y , x).
    ***Hence, the rotation of the point (x, y) through 270 degrees clockwise becomes (-y, x)

    Grade-8
    Mathematics

    In rotation, the point (x, y) after moving 180°counter-clockwise will be

    Given That:
    In rotation, the point (x, y) after moving 180°counter-clockwise will be
    >>>Since, it is counter clockwise rotation the angle of rotation remains positive.
    >>>Therefore, the angle of rotation alpha becomes 180 degrees.
    >>>The new coordinates becomes:
    =  (x cosalpha - y sinalpha , y cosalpha + x sinalpha)
                         = (x cos(180) -y sin(180) , y cos(180) + x sin(180))
    = (-x , -y).
    ***Hence, the rotation of the point (x, y) through 180 degrees counter clockwise becomes (-x, -y).

    In rotation, the point (x, y) after moving 180°counter-clockwise will be

    MathematicsGrade-8

    Given That:
    In rotation, the point (x, y) after moving 180°counter-clockwise will be
    >>>Since, it is counter clockwise rotation the angle of rotation remains positive.
    >>>Therefore, the angle of rotation alpha becomes 180 degrees.
    >>>The new coordinates becomes:
    =  (x cosalpha - y sinalpha , y cosalpha + x sinalpha)
                         = (x cos(180) -y sin(180) , y cos(180) + x sin(180))
    = (-x , -y).
    ***Hence, the rotation of the point (x, y) through 180 degrees counter clockwise becomes (-x, -y).

    parallel

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