Question
Number of solutions for is
- One solution
- No solution
- Infinity many solution
- Cannot be determined
Hint:
An equation contains constants, variables and an equal sign. It has two sides called LHS and RHS. A linear equation in one variable is an equation with only one variable and the highest power of the variable should be one. Here, we have to find the number of solutions of the given linear equation in one variable which can be done by writing the given equation in standard form and comparing the it with the standard equation.
The correct answer is: One solution
The given equation is
Here, we have to find the number of solutions for the given equation.
Step 1: Solve the bracket.
Since, the variables and constants in both sides are different, so this equation don't have infinitely many solutions.
Bring all the terms containing variables in one side by operating same numbers on both sides to balance the equation.
Step 2: Multiply 10 on both sides.(LCM of 2 and 5 is 10.)
Step 3: Solve the brackets on both sides.
25x-125= -4x+16
Step 4: Add 4x on both sides.
25x-125+4x= -4x+16+4x
25x-125+4x= 16
Step 5: Add 125 on both sides.
25x-125+4x+125= 16+125
25x+4x= 16+125
Step 6: Solve both sides.
29x= 141 ...........(1)
Step 7: Write the eq. 1 in standard form,i.e., ax+b=0
29x-141=0 ...............(2)
Step 8: Compare eq. 2 with the standard equation.
On comparing eq. 2 with the standard equation we have, a= 29 and b= -141.
Since, x=
So, the equation has only one solution.
therefore, the correct option is a,i.e., one solution.
Standard form of linear equation in one variable is ax+b=0. If x=, then the solutions will be one. If both sides of the equation have same variable and constants then the equation has infinitely many solution.
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