Question
The floor of building consists of 2000 tiles which are rhombus shaped and each of its diagonals are 40 cm and 25 cm in length. Find the total cost of polishing the floor, if the cost per m² is $5.
- $2500
- $500
- $1500
- $2000
The correct answer is: $500
$ 5000
Area of rhombus = 1/2x product of diagonals
Area of 1 tile = ½ x 40 x 25 = 5000 sq cm = 5000/ 10000 m2 = 0.5 m2
Area of 2000 tiles = 2000 x 0.5 = 1000 m2
Cost per m2 = $5
Cost of 1000 m2 = 1000 x 5 = $ 5000
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