Question
Solve the following pair of linear (simultaneous) equations by the method of elimination:
x + y = 7
5x + 12y = 7
- x = 11 and y = -4
- x = 11 and y = -5
- x = 13 and y = 6
- x = -2 and y = 5
Hint:
Here we have to solve the system of equation by elimination. The equation are x + y = 7 and 5x + 12y = 7. In elimination method we have to multiply in both equation by number which is lowest common multiple for one of the variable. Then perform the addition or subtraction to eliminate the variable and substitute the that variable in equation and find the other equation.
The correct answer is: x = 11 and y = -4
Here we have to solve the system of equation that is x + y = 7 and 5x + 12y = 7 by elimination method.
Firstly we have two equations,
x + y = 7 .... (1)
5x + 12y = 7 ....(2)
Multiply eq. (1) by 5, we get
5x + 5y = 35 ....(3)
Subtracting eq.(2) from eq.(3)
5x + 5y = 35
5x + 12y = 7
− − −
---------------------
−7y = 28
y = −4
Substituting value of y in eq,(1), we get,
x − 4 = 7
x = 11
Put x= 11 in eq (1)
x + y = 7
11 + y = 7
y = 7 - 11
y = -4
Therefore, the solution of following pair linear equation is x= 11 and y = -4.
The correct answer is x= 11 and y = -4
In this question , we have to solve the system of equation by elimination method. In elimination method you have two equation. we have to multiply in both equation by number which is lowest common multiple for one of the variable. Then perform the addition or subtraction to eliminate the variable and substitute the that variable in equation and find the other equation.
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