Mathematics
Grade5
Easy

Question

Subtract 5 over 6 minus 11 over 8.

  1. 11 over 24
  2. 13 over 24
  3. 5 over 8
  4. 3 over 7

hintHint:

In this question we have to add two fractions for that we have to make denominator same this can be done by taking LCM. LCM is the least common multiple of two integers. We will use the prime factorization method to find the LCM. In prime factorization method the simply put the factor of each number and then for LCM we take product of factors, but we consider the repeated factors only one time but with highest exponent.

The correct answer is: 13 over 24


    11 over 8 space equals space 33 over 24 space space open parentheses Multiply space with space 3 close parentheses
5 over 6 space equals space 20 over 24 space space open parentheses Multiply space with space 4 close parentheses
33 over 24 space minus space 20 over 24 equals 13 over 24
    Step1: First we will write all the prime factors of the denominators
    In this question the denominators are 6 and 8.
    Factors of 6 are: 3 cross times 2 =3 to the power of 1 space cross times 2 to the power of 1
    Factors of 8 are:2 cross times 2 cross times 2 =2 cubed
    Step2:  For calculating the LCM we will multiply the factors by considering the common factors only one time but with highest exponent
    In this case the factor 2 is common in both 6 and 8 so we will multiply it only once with the highest exponent.
    LCM(6 comma 8) = 2 cubed cross times 3 to the power of 1
    LCM(6 comma 8) = 24

    Step3: Now what we do is divide the LCM by each denominator and multiply the numerator by quotient and then subtract them
    So, 24 over 6 equals 4
    and 24 over 8 equals 3
    So, we will multiply the numerator of 6 by 4 and numerator of 8 by 3.
    fraction numerator 5 cross times 4 space minus space 11 cross times 3 over denominator 24 end fraction space space equals space fraction numerator negative 13 over denominator 24 end fraction

    So, the subtraction of 5 over 6 space space a n d space 11 over 8 is fraction numerator negative 13 over denominator 24 end fraction.

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