Question
What do we get after expanding (p + 3q - 2z)2?
- p2 + 9q2 + 4z2 + 6pq – 12qz + 4zp
- p2 + 9q2 + 4z2 + 12pq + 12qz + 4zp
- p2 + 9q2 + 4z2 – 12pq – 12qz – 4zp
- p2 + 9q2 + 4z2 + 6pq – 12qz – 4zp
The correct answer is: p2 + 9q2 + 4z2 + 6pq – 12qz – 4zp
We know that (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca
(p + 3q - 2z)2can also be written as (p + 3q + ( - 2z))2.
Here, a = p, b = 3q and c = - 2z
Therefore, using that formula we get (p + 3q + ( - 2z))2
= p2 + (3q)2 + ( - 2z)2 + 2(p)(3q) + 2(3q)( - 2z) + 2( - 2z)(p)
= p2 + 9q2 + 4z2 + 6pq – 12qz – 4zp.
= p2 + (3q)2 + ( - 2z)2 + 2(p)(3q) + 2(3q)( - 2z) + 2( - 2z)(p)
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