Without multiplying, order the following products from the least to the greatest.
A. $2 over 3 cross times 8 over 3$
B. $2 over 3 cross times 3 over 5$
C. $2 over 3 cross times 9 over 9$

$open parentheses 1 plus 2 1 over 8 close parentheses cross times 1 half$

Follow the BODMAS rule. Let’s convert the mixed fraction into the improper fraction. We get, ((8 x 2 +1)/8) =17/8. on adding the terms inside the bracket, we get 1 + 17/8= 25/8. Now, lets calculate 25/8 x 1/2; we get 25/16.

$open parentheses 1 plus 2 1 over 8 close parentheses cross times 1 half$

$open parentheses 7 1 over 7 plus 1 over 7 close parentheses cross times 1 over 7$

convert the mixed fractions into improper fractions. Then follow BODMAS rule. We get ((7 x7)+ 1)/7 + 1/7 = 50/7 + 1/7 = 51/7 . Now, let’s multiply 51/7 x 1/7, we get 51/49

$open parentheses 7 1 over 7 plus 1 over 7 close parentheses cross times 1 over 7$

convert the mixed fractions into improper fractions. Then follow BODMAS rule. We get ((7 x7)+ 1)/7 + 1/7 = 50/7 + 1/7 = 51/7 . Now, let’s multiply 51/7 x 1/7, we get 51/49

$open parentheses 1 2 over 5 plus 1 third close parentheses cross times 7 over 3$

convert the mixed fractions into improper fractions. Then follow BODMAS rule. We get ((5 x1)+ 2)/5 + 7/3 = 26/15 . Now, let’s multiply 26/15 x 7/13, we get 14/15

$open parentheses 1 2 over 5 plus 1 third close parentheses cross times 7 over 3$

convert the mixed fractions into improper fractions. Then follow BODMAS rule. We get ((5 x1)+ 2)/5 + 7/3 = 26/15 . Now, let’s multiply 26/15 x 7/13, we get 14/15

$1 2 over 5 cross times 2 over 3$

Let’s convert the mixed fractions into improper fractions. We get ((5 x 1) +2)/5 and 2/3, i.e., 7/5 and 2/3. Let’s calculate the product 7/5 x 2/3 we get 14/15

$1 2 over 5 cross times 2 over 3$

Let’s convert the mixed fractions into improper fractions. We get ((5 x 1) +2)/5 and 2/3, i.e., 7/5 and 2/3. Let’s calculate the product 7/5 x 2/3 we get 14/15

$open parentheses 1 over 7 plus 1 half close parentheses cross times 1 7 over 2$

Follow the BODMAS rule. So, first let’s add 1/7 and 1/3, we get 9/14. Now , convert the mixed fraction into improper fraction, we get 9/2. Multiplying 9/14 x 9/2 , we get 81/28. This isn’t given in any of the options, so, answer is none of the above.

$open parentheses 1 over 7 plus 1 half close parentheses cross times 1 7 over 2$

$2 over 15 cross times 1 1 half$

Let’s convert the mixed fractions into improper fractions. We get 2/15 and ((2 x 1) + 1)/2, i.e., 2/15 and 3/2. Let’s calculate the product 2/15 x 3/2 we get 1/5

$2 over 15 cross times 1 1 half$

Let’s convert the mixed fractions into improper fractions. We get 2/15 and ((2 x 1) + 1)/2, i.e., 2/15 and 3/2. Let’s calculate the product 2/15 x 3/2 we get 1/5

Compare using >, <, or =
$17 8 over 7 space box enclose blank end enclose space 17$ .

$2 over 2 cross times 1 1 third$

Let’s convert the mixed fractions into improper fractions. We get 2/2 and ((3 x 1) + 1)/3, i.e., 2/2 and 4/3. Let’s calculate the product 2/2 x 4/3 we get 4/3

$2 over 2 cross times 1 1 third$

Let’s convert the mixed fractions into improper fractions. We get 2/2 and ((3 x 1) + 1)/3, i.e., 2/2 and 4/3. Let’s calculate the product 2/2 x 4/3 we get 4/3

$1 1 over 20 cross times 1 over 7$

Let’s convert the mixed fractions into improper fractions. We get ((20 x 1) +1)/20 and 1/7 i.e., 21/20 and 1/7. Let’s calculate the product 21/20 x 1/7 we get 3/20

$1 1 over 20 cross times 1 over 7$

Let’s convert the mixed fractions into improper fractions. We get ((20 x 1) +1)/20 and 1/7 i.e., 21/20 and 1/7. Let’s calculate the product 21/20 x 1/7 we get 3/20

$1 22 over 123 cross times 143 over 20 cross times 0$

Anything multiplied by 0 is 0. Hence, the answer is 0.

$1 22 over 123 cross times 143 over 20 cross times 0$

Anything multiplied by 0 is 0. Hence, the answer is 0.

$3 1 fifth cross times 10 over 2$

Let’s convert the mixed fractions into improper fractions. We get ((5 x 3) +1)/5 and 10/2, i.e., 16/5 and 10/2. Let’s calculate the product 16/5 x 10/5 we get 16

$3 1 fifth cross times 10 over 2$

Let’s convert the mixed fractions into improper fractions. We get ((5 x 3) +1)/5 and 10/2, i.e., 16/5 and 10/2. Let’s calculate the product 16/5 x 10/5 we get 16

$1 1 over 9 cross times 2 1 third$

Lets convert the mixed fractions into improper fractions. We get ((9 x 1) +1)/9 and ((3 x 2)+ 1)/3, i.e., 10/9 and7/3. Let’s calculate the product 10/9 x 7/3 we get 70/27

$1 1 over 9 cross times 2 1 third$

Lets convert the mixed fractions into improper fractions. We get ((9 x 1) +1)/9 and ((3 x 2)+ 1)/3, i.e., 10/9 and7/3. Let’s calculate the product 10/9 x 7/3 we get 70/27

$4 1 half cross times 1 half$

Lets convert the mixed fractions into improper fractions. We get ((2 x 4) +1)/2 and 1/2 i.e., 9/2 and 1/2. Let’s calculate the product 9/2 x 1/2 we get 9/4

$4 1 half cross times 1 half$

Lets convert the mixed fractions into improper fractions. We get ((2 x 4) +1)/2 and 1/2 i.e., 9/2 and 1/2. Let’s calculate the product 9/2 x 1/2 we get 9/4

$3 3 over 9 cross times 1 1 third$

Lets convert the mixed fractions into improper fractions. We get ((9 x 3) +3)/9 and ((3 x 1)+ 1)/3, i.e., 30/9 and 4/3. Let’s calculate the product 30/9 x 4/3 . we get 40/9

$3 3 over 9 cross times 1 1 third$