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Easy

Question

(7532 + 100 y2) + 10 (10 y2 – 110) The expression above can be written in the form
ay2 + b , where a and b are constants. What is the value of a + b ?

The correct answer is: 6632


    HINT – Open the brackets
    SOLUTION – Let he given expression be
    F(y) = (7532 + 100 y2) + 10 (10 y2 – 110)
    = 7532 + 100 y2 + 100 y2 – 1100
    = 200 y2 + 6432
    Comparing with the expression given in the question a y2 + b
    We get,  a = 200 and b = 6432
    rightwards double arrowa + b =  200 + 6432
    =  6632
    Hence, answer is 6632

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