Maths-
General
Easy
Question
Find the area of an isosceles triangle whose one side is 10 cm greater than each of its equal sides and perimeter is 100 cm.
Hint:
Let two equal sides be x cm
The correct answer is: 200√5 cm2
It is given that one side is 10 cm greater than each of its equal sides.
Let two equal sides be x cm
So, third side = x + 10
Perimeter = 100 cm.
i.e. Sum of all sides = 100
x + x + x + 10 = 100
3x = 90. ⇒ x = 30 cm
Two equal sides = 30 cm
Third side = 30 + 10 = 40 cm
Using Heron’s formula,
Area of triangle = 
where s = 
s = 
= 50
Area of triangle = 
= 
= 
= 
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