Question
Solve:
and 
Hint:
Let
and
now we get the equation in a and b
Now find values of a and b .After finding a and b substitute them in
and
and find the values of x and y.
The correct answer is: x = 3 ; y = 2
Let
now we get the equation in a and b
— eq1
—eq2
Step 1 :- find value of b by eliminating a
Do eq2 - 3(eq1) to eliminate a


∴ b = 1
Step 2 :- find value of a by substituting b=1 in eq1
5a - 2b = -1


∴ a = 1/5
Step 3 :- substitute a and b in 
and 
Now let x + y = 5 — eq3
x - y = 1— eq4
Step 4:- finding x by eliminating y
Adding eq3 and eq4 we get



Step 5:- finding y by substituting value of x in eq3



and y = 2 is the solution to the given pair of equation
Step 1 :- find value of b by eliminating a
Do eq2 - 3(eq1) to eliminate a
Step 2 :- find value of a by substituting b=1 in eq1
Step 3 :- substitute a and b in
Step 4:- finding x by eliminating y
Adding eq3 and eq4 we get
Related Questions to study
Solve the pair of linear equations,
Also find p if p = 2x + 3
Solve the pair of linear equations,
Also find p if p = 2x + 3
Solve:
by using substitution method.
Solve:
by using substitution method.
Solve: 3x + y = 8; 5x + y = 10 by using elimination method.
Solve: 3x + y = 8; 5x + y = 10 by using elimination method.
Solve
and
by using elimination method.
Solve
and
by using elimination method.
Solve by using elimination method: 
Solve by using elimination method: 
Solve by using elimination method.
.
Solve by using elimination method.
.
Solve the following equation by balancing on both sides: b) 6n+7= 3n+25
Solve the following equation by balancing on both sides: b) 6n+7= 3n+25
Solve the following equation by balancing on both sides: a) 5m+9 = 4m + 23
Solve the following equation by balancing on both sides: a) 5m+9 = 4m + 23
Solve: 
Solve: 

Which of the following could be the x-coordinate of a solution to the system of equations above?
Note:
If we had to find the y-coordinate of the system of equations, then we put this value of x in the equation to get the value of y. Here, we got a quadratic equation of x, which did not have any term containing x, so it was easier to solve. If the quadratic equation was of the form
, then we would use the quadratic formula
to solve the equation.

Which of the following could be the x-coordinate of a solution to the system of equations above?
Note:
If we had to find the y-coordinate of the system of equations, then we put this value of x in the equation to get the value of y. Here, we got a quadratic equation of x, which did not have any term containing x, so it was easier to solve. If the quadratic equation was of the form
, then we would use the quadratic formula
to solve the equation.
Solve the equation and check your result 6(3m + 2) – 2(6m – 1) = 3(m – 8) – 6(7m – 6) +9m
Solve the equation and check your result 6(3m + 2) – 2(6m – 1) = 3(m – 8) – 6(7m – 6) +9m
Solve and check your answer: 3x – 2(2x – 5) = 2(x + 3) – 8
Solve and check your answer: 3x – 2(2x – 5) = 2(x + 3) – 8
Solve: 16 = 4 + 3(x + 2)
Solve: 16 = 4 + 3(x + 2)

The graph of the function f is shown in the xy-plane above, where y =f
. Which of the following functions could define f ?
Note:
We need to know properties about factors, multiplicity, leading co-efficients and turning points to find out the function from a graph.

The graph of the function f is shown in the xy-plane above, where y =f
. Which of the following functions could define f ?
Note:
We need to know properties about factors, multiplicity, leading co-efficients and turning points to find out the function from a graph.