Maths-
General
Easy
Question
The trajectory of the water from Fountain A is represented by a function in standard form while the trajectory of the water from Fountain B is represented by table of values. Compare the vertex of each function. Which trajectory reached greatest height in feet?
Hint:
For a quadratic function is in standard form, f(x)=ax2+bx+c.
Axis of symmetry x=−b/2a
Vertex The vertex of the parabola is located at a pair of coordinates which we will call (h, k). where h is value of x in axis of symmetry formula and k is f(h).
Solution:-
The correct answer is: B reached greatest height.
We have given two fountains A and B
For fountain A trajectory
f(x) = -x2 + 2x + 8
x = -2 / 2(-1)
= -2 / -2
x = 1
The x coordinate of the vertex is the same:
h = 1
The y coordinate of the vertex is :
k = f(h)
k = -(h)2 + 2(h) + 8
k = -(1)2 + 2(1) + 8
k = -1 + 2 + 8
k = 9
Therefore, the vertex is (1 , 9)
For fountain B trajectory
Height of the fountain can be measured by y coordinate of the trajectory
So, maximum y coordinate of fountain B is 10 in the given values
And the y coordinate of vertex of fountain A is 9
So y- coordinate of fountain B is more than of fountain A
Therefore , Fountain B reached greatest height.
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