Maths-
General
Easy

Question

A box contains 4 packs of chocolates. Anusha picks out a pack at random. What is the probability that she picks
A) Perk?
B) Kitkat?

  1. fraction numerator 1 over denominator 4 end fraction comma fraction numerator 1 over denominator 2 end fraction    
  2. fraction numerator 1 over denominator 3 end fraction comma fraction numerator 2 over denominator 3 end fraction    
  3. fraction numerator 3 over denominator 4 end fraction comma fraction numerator 2 over denominator 3 end fraction    
  4. none of these    

hintHint:

Probability refers to potential. A random event's occurrence is the subject of this area of mathematics. The range of the value is 0 to 1. Here we have given a box that contains 4 packs of chocolates. Anusha picks out a pack at random. We have to find the probability that she pick Perk and Kitkat.

The correct answer is: fraction numerator 1 over denominator 4 end fraction comma fraction numerator 1 over denominator 2 end fraction


    Probability is a way to gauge how likely something is to happen. Many things are difficult to forecast with absolute confidence. Using it, we can only make predictions about how probable an event is to happen or its chance of happening. Probability can range from 0 to 1, with 0 denoting an impossibility and 1 denoting a certainty.
    According to the probability formula, the likelihood that an event will occur is equal to the proportion of favorable outcomes to all outcomes.
    Probability of event to happen P(E) = Number of favourable outcomes/Total Number of outcomes
    So here in this question, we have given the total number of outcomes as 4 packs.
    So probability that she picks perk is:
    P(Perk) = 1/4
    So probability that she picks Kitkat is:
    P(Kitkat) = 2/4 = 1/2

    Here we used the concept of probability to find the answer using events. A set of results from an experiment might be referred to as a probability event. In other words, a probability definition of an event is the subset of the relevant sample space. So the probabilities are fraction numerator 1 over denominator 4 end fraction comma fraction numerator 1 over denominator 2 end fraction.

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