Question
Candies cost $2 an ounce and have 500 calories in an ounce. Cookies cost $3 an ounce and have 400calories in an ounce. A mixture of candies and cookies costs $29 and has 4,800 calories. Create a system of equations to model this scenario. How many ounces of candies are there in the mixture?
Hint:
candies cost $2 an ounce and have 500 calories in an ounce. Cookies cost $3 an ounce and have 400calories in an ounce.
Let the no. of ounces of candy be x and no. of ounces of cookies be y
Total cost = cost of x ounces candy + cost of y ounces cookies = $29
Total no. of calories = calories in x ounces candy + calories in y ounces cookies = 4,800
The correct answer is: 4 ounces.
Ans :-The no. of ounces of candy is 4 ounces in the mixture .
Explanation :-
Given ,candies cost $2 an ounce and have 500 calories in an ounce. Cookies cost $3 an ounce and have 400calories in an ounce.
Step 1:Frame the system of linear equations based on given conditions
Let the no. of ounces of candy be x and no. of ounces of cookies be y
Total cost = cost of x ounces candy + cost of y ounces cookies =
x cost of each ounce candy + y cost of each ounce cookies = $29
— Eq1
Total no. of calories = calories in x ounces candy + calories in y ounces cookies =
x calories in each ounce candy + y calories in each ounce cookies = 4,800
— Eq2
Step 2:- eliminate x to find the value of y .
Doing 5(Eq1) -2(Eq2) to eliminate x .
∴y = 7
Step 3:- find x by substituting the value of y in eq1.
∴x =4
∴ we get the no. of ounces of candy be x = 4 ounces.
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