Maths-
General
Easy
Question
50 animals are there in a shed. Some of the animals have 2 legs and the rest of them have 4 legs. In total there are 172 legs. Frame the system of linear equations and use elimination method to solve .
Hint:
let the no. of 2 leg animals be x and let the number of 4 leg animals be y
Given total no. of animals = no. of 2 leg animals + no. of 4 leg animals = 50
Given no. of legs = 2
no. of 2 leg animals + 4no. of 4 leg animals = 172.
The correct answer is: 24
Ans :- The no. of 2 leg animals are 26 and no. of 4 leg animals are 24.
Explanation :-
Step 1:- Frame the equations
let the no. of 2 leg animals be x and let the number of 4 leg animals be y
Given total no. of animals = no. of 2 leg animals + no. of 4 leg animals = 50
i. e x + y = 50 — eq1
Given no. of legs = 2no. of 2 leg animals + 4no. of 4 leg animals = 172.
i. e 2x+4y = 172 — eq2
So the equations are x + y = 50 and 2x + 4y = 172
Step 2 :- eliminate x to find value of y
Doing eq2 - 2eq1 to eliminate x
We get 
∴ y = 24
Step 3:- substitute the value of y in eq1 to get the value of x
∴ x = 26
∴The no. of 2 leg animals are 26 and no. of 4 leg animals are 24.
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