Maths-
General
Easy

Question

Eleven animals of a circus have to be placed in eleven cages, one in each cage. If four of the cages are too small for six of the animals, the number of ways of caging the animals is-

  1. 7P6. 5!    
  2. 6P4. 7!    
  3. 11C4. 7!    
  4. None of these    

hintHint:

From the statement we can conclude that :There are 6 large animals and 5 small animals  also there are 7 large cages and 4 small cages. Arrange the animals accordingly.

The correct answer is: 7P6. 5!


    We have been given that eleven animals of a circus have to be placed in eleven cages, one in each cage. If four of the cages are too small for six of the animals

    From the above statement we can conclude that :There are 6 large animals and 5 small animals  also there are 7 large cages and 4 small cages.


    6 large animals can be caged in 7 large cages in P presuperscript 7 subscript 6 space end subscript equals space 7 factorial thin space ways.

    5 small animals can be caged in remaining 5 cages (4 small + 1 large) in 5! ways.

    Thus, the number of ways of caging the animals is = P presuperscript 7 subscript 6 space cross times space 5 factorial

     

     

     

     

     

     

    Related Questions to study

    General
    Maths-

    Eight chairs are numbered from 1 to 8. Two women and three men wish to occupy one chair each. First women choose the chairs from amongst the chairs marked 1 to 4; and then the men select the chairs from the remaining. The number of possible arrangements is-

    It is important to note that we have used a fact that C presuperscript n subscript r = P presuperscript n subscript r space. space r factorial. This can be understood as we know that C presuperscript n subscript r = fraction numerator n factorial over denominator left parenthesis n minus r right parenthesis factorial space r factorial end fractionand P presuperscript n subscript r = fraction numerator n factorial over denominator left parenthesis n minus r right parenthesis factorial space end fraction  . So, substituting this we have C presuperscript n subscript r = P presuperscript n subscript r space. space r factorial . 

    Eight chairs are numbered from 1 to 8. Two women and three men wish to occupy one chair each. First women choose the chairs from amongst the chairs marked 1 to 4; and then the men select the chairs from the remaining. The number of possible arrangements is-

    Maths-General

    It is important to note that we have used a fact that C presuperscript n subscript r = P presuperscript n subscript r space. space r factorial. This can be understood as we know that C presuperscript n subscript r = fraction numerator n factorial over denominator left parenthesis n minus r right parenthesis factorial space r factorial end fractionand P presuperscript n subscript r = fraction numerator n factorial over denominator left parenthesis n minus r right parenthesis factorial space end fraction  . So, substituting this we have C presuperscript n subscript r = P presuperscript n subscript r space. space r factorial . 

    General
    Maths-

    A tea party is arranged of 16 persons along two sides of a long table with 8 chairs on each side. 4 men wish to sit on one particular side and 2 on the other side. In how many ways can they be seated ?

    Whenever we face such types of problems the key point is to make special arrangements for the people who are in need of it, then arrange the remaining. Now combination comes with permutation as there are possibilities of these 8 people sitting on one side to rearrange. Thus this concept into consideration, to get through the answer.

    A tea party is arranged of 16 persons along two sides of a long table with 8 chairs on each side. 4 men wish to sit on one particular side and 2 on the other side. In how many ways can they be seated ?

    Maths-General

    Whenever we face such types of problems the key point is to make special arrangements for the people who are in need of it, then arrange the remaining. Now combination comes with permutation as there are possibilities of these 8 people sitting on one side to rearrange. Thus this concept into consideration, to get through the answer.

    General
    Maths-

    If (m+n) P2 = 56 and m–nP2 = 12 then (m, n) equals-

    If (m+n) P2 = 56 and m–nP2 = 12 then (m, n) equals-

    Maths-General
    parallel
    General
    physics-

    A thin uniform annular disc (see figure) of mass M has outer radius 4 R and inner radius 3 R. The work required to take a unit mass from point P on its axis to infinity is

    A thin uniform annular disc (see figure) of mass M has outer radius 4 R and inner radius 3 R. The work required to take a unit mass from point P on its axis to infinity is

    physics-General
    General
    physics-

    The two bodies of mass m subscript 1 end subscript and m subscript 2 end subscript left parenthesis m subscript 1 end subscript greater than m subscript 2 end subscript right parenthesis respectively are tied to the ends of a massless string, which passes over a light and frictionless pulley. The masses are initially at rest and the released. Then acceleration of the centre of mass of the system is

    The two bodies of mass m subscript 1 end subscript and m subscript 2 end subscript left parenthesis m subscript 1 end subscript greater than m subscript 2 end subscript right parenthesis respectively are tied to the ends of a massless string, which passes over a light and frictionless pulley. The masses are initially at rest and the released. Then acceleration of the centre of mass of the system is

    physics-General
    General
    maths-

    If x equals 1 plus 3 a plus 6 a squared plus 10 a cubed plus midline horizontal ellipsis. to straight infinity terms, vertical line a vertical line less than 1 comma y equals 1 plus 4 a plus 10 a squared plus 20 a cubed plus midline horizontal ellipsis straight infinity terms, vertical line a vertical line less than 1, then x colon y

    If x equals 1 plus 3 a plus 6 a squared plus 10 a cubed plus midline horizontal ellipsis. to straight infinity terms, vertical line a vertical line less than 1 comma y equals 1 plus 4 a plus 10 a squared plus 20 a cubed plus midline horizontal ellipsis straight infinity terms, vertical line a vertical line less than 1, then x colon y

    maths-General
    parallel
    General
    Maths-

    The coefficient of x to the power of negative n end exponent in left parenthesis 1 plus x right parenthesis to the power of n end exponent open parentheses 1 plus fraction numerator 1 over denominator x end fraction close parentheses to the power of n end exponent is

    The coefficient of x to the power of negative n end exponent in left parenthesis 1 plus x right parenthesis to the power of n end exponent open parentheses 1 plus fraction numerator 1 over denominator x end fraction close parentheses to the power of n end exponent is

    Maths-General
    General
    maths-

    open parentheses 1 plus x plus x squared plus horizontal ellipsis plus x to the power of p close parentheses to the power of n equals a subscript 0 plus a subscript 1 x plus a subscript 2 x squared plus horizontal ellipsis plus a subscript n p end subscript x to the power of n p end exponent not stretchy rightwards double arrow a subscript 1 plus 2 a subscript 2 plus 3 a subscript 3 plus horizontal ellipsis plus n p

    open parentheses 1 plus x plus x squared plus horizontal ellipsis plus x to the power of p close parentheses to the power of n equals a subscript 0 plus a subscript 1 x plus a subscript 2 x squared plus horizontal ellipsis plus a subscript n p end subscript x to the power of n p end exponent not stretchy rightwards double arrow a subscript 1 plus 2 a subscript 2 plus 3 a subscript 3 plus horizontal ellipsis plus n p

    maths-General
    General
    chemistry-

    Compounds (A) and (B) are – 

    Compounds (A) and (B) are – 

    chemistry-General
    parallel
    General
    Maths-

    2 times C subscript 0 plus 5 times C subscript 1 plus 8 times C subscript 2 plus horizontal ellipsis plus left parenthesis 2 plus 3 n right parenthesis times C subscript n equals

    2 times C subscript 0 plus 5 times C subscript 1 plus 8 times C subscript 2 plus horizontal ellipsis plus left parenthesis 2 plus 3 n right parenthesis times C subscript n equals

    Maths-General
    General
    maths-

    A triangle is inscribed in a circle. The vertices of the triangle divide the circle into three arcs of length 3, 4 and 5 units. Then area of the triangle is equal to:

    A triangle is inscribed in a circle. The vertices of the triangle divide the circle into three arcs of length 3, 4 and 5 units. Then area of the triangle is equal to:

    maths-General
    General
    Maths-

    If one root of the equation a x squared plus b x plus c equals 0 is reciprocal of the one of the roots of equation  a subscript 1 x squared plus b subscript 1 x plus c subscript 1 equals 0 then

    If one root of the equation a x squared plus b x plus c equals 0 is reciprocal of the one of the roots of equation  a subscript 1 x squared plus b subscript 1 x plus c subscript 1 equals 0 then

    Maths-General
    parallel
    General
    Maths-

    If the quadratic equation a x squared plus 2 c x plus b equals 0 and a x squared plus 2 b x plus c equals 0 left parenthesis b not equal to c right parenthesis have a common root then a plus 4 b plus 4 c is equal to

    If the quadratic equation a x squared plus 2 c x plus b equals 0 and a x squared plus 2 b x plus c equals 0 left parenthesis b not equal to c right parenthesis have a common root then a plus 4 b plus 4 c is equal to

    Maths-General
    General
    physics-

    Two blocks of masses 10 kg and 4 kg are connected by a spring of negligible mass and placed on frictionless horizontal surface. An impulsive force gives a velocity of 14m s to the power of negative 1 end exponent to the heavier block in the direction of the lighter block. The velocity of centre of mass of the system at that very moment is

    Two blocks of masses 10 kg and 4 kg are connected by a spring of negligible mass and placed on frictionless horizontal surface. An impulsive force gives a velocity of 14m s to the power of negative 1 end exponent to the heavier block in the direction of the lighter block. The velocity of centre of mass of the system at that very moment is

    physics-General
    General
    Maths-

    In a Δabc if b+c=3a then cot invisible function application straight B over 2 times cot invisible function application straight C over 2 has the value equal to –

    In a Δabc if b+c=3a then cot invisible function application straight B over 2 times cot invisible function application straight C over 2 has the value equal to –

    Maths-General
    parallel

    card img

    With Turito Academy.

    card img

    With Turito Foundation.

    card img

    Get an Expert Advice From Turito.

    Turito Academy

    card img

    With Turito Academy.

    Test Prep

    card img

    With Turito Foundation.