Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Offsite Campus Turito Championship

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

Maths-

General

Easy

Question

If $A equals open curly brackets 1 comma blank 2 comma blank 3 comma blank 4 comma blank 5 close curly brackets comma blank B equals open curly brackets 2 comma blank 4 comma blank 6 close curly brackets comma blank C equals left curly bracket 3 comma blank 4 comma blank 6 right curly bracket$ , then $left parenthesis A union B right parenthesis intersection C$ is

(a) {3, 4, 6}
{1, 2, 3}
{1, 4, 3}
None of these

The correct answer is: (a) {3, 4, 6}

$because blank A union B equals open curly brackets 1 comma blank 2 comma blank 3 comma blank 4 comma blank 5 comma blank 6 close curly brackets$
$therefore blank open parentheses A union B close parentheses intersection C equals open curly brackets 1 comma blank 2 comma blank 3 comma blank 4 comma blank 5 comma blank 6 close curly brackets intersection open curly brackets 3 comma blank 4 comma blank 6 close curly brackets$
$equals left curly bracket 3 comma blank 4 comma blank 6 right curly bracket$

Related Questions to study

Let $A equals open curly brackets 1 comma blank 2 comma blank 3 comma blank 4 close curly brackets comma blank B equals left curly bracket 2 comma blank 4 comma blank 6 right curly bracket$ . Then, the number of sets $C$ such that $A intersection B subset of or equal to C subset of or equal to A blank union B$ is

Let $A equals open curly brackets 1 comma blank 2 comma blank 3 comma blank 4 close curly brackets comma blank B equals left curly bracket 2 comma blank 4 comma blank 6 right curly bracket$ . Then, the number of sets $C$ such that $A intersection B subset of or equal to C subset of or equal to A blank union B$ is

If $A equals open curly brackets theta blank colon cos invisible function application theta greater than negative fraction numerator 1 over denominator 2 end fraction comma 0 less or equal than theta less or equal than pi close curly brackets$ and
$B equals open curly brackets theta blank colon sin invisible function application theta greater than fraction numerator 1 over denominator 2 end fraction comma fraction numerator pi over denominator 3 end fraction less or equal than theta less or equal than pi close curly brackets comma$ then

If $A equals open curly brackets theta blank colon cos invisible function application theta greater than negative fraction numerator 1 over denominator 2 end fraction comma 0 less or equal than theta less or equal than pi close curly brackets$ and
$B equals open curly brackets theta blank colon sin invisible function application theta greater than fraction numerator 1 over denominator 2 end fraction comma fraction numerator pi over denominator 3 end fraction less or equal than theta less or equal than pi close curly brackets comma$ then

In a class of 30 pupils 12 take needls work, 16 take physics and 18 take history. If all the 30 students take at least one subject and no one takes all three, then the number of pupils taking 2 subjects is

In a class of 30 pupils 12 take needls work, 16 take physics and 18 take history. If all the 30 students take at least one subject and no one takes all three, then the number of pupils taking 2 subjects is

parallel

If $A equals left curly bracket x blank colon x$ is a multiple of $blank 4 right curly bracket$ and,
$B equals left curly bracket x blank colon x blank$ is a multiple of $blank 6 right curly bracket$ , then $A intersection B$ consists of multiples of

If $A equals left curly bracket x blank colon x$ is a multiple of $blank 4 right curly bracket$ and,
$B equals left curly bracket x blank colon x blank$ is a multiple of $blank 6 right curly bracket$ , then $A intersection B$ consists of multiples of

In a city 20% of the population travels by car, 50% travels by bus and 10% travels by both car and bus. Then, persons travelling by car or bus is

In a city 20% of the population travels by car, 50% travels by bus and 10% travels by both car and bus. Then, persons travelling by car or bus is

Let $Y equals open curly brackets 1 comma blank 2 comma blank 3 comma blank 4 comma blank 5 close curly brackets comma blank A open curly brackets 1 comma blank 2 close curly brackets comma blank B equals left curly bracket 3 comma blank 4 comma blank 5 right curly bracket$ and $ϕ$ denotes null set. If $left parenthesis A cross times B right parenthesis$ denotes cartesian product of the sets $A$ and $B$ ; then $open parentheses Y cross times A close parentheses intersection left parenthesis Y cross times B right parenthesis$ is

Let $Y equals open curly brackets 1 comma blank 2 comma blank 3 comma blank 4 comma blank 5 close curly brackets comma blank A open curly brackets 1 comma blank 2 close curly brackets comma blank B equals left curly bracket 3 comma blank 4 comma blank 5 right curly bracket$ and $ϕ$ denotes null set. If $left parenthesis A cross times B right parenthesis$ denotes cartesian product of the sets $A$ and $B$ ; then $open parentheses Y cross times A close parentheses intersection left parenthesis Y cross times B right parenthesis$ is

parallel

If $A equals open curly brackets p element of N colon p blank i s blank a blank p r i m e blank a n d blank p equals fraction numerator 7 n to the power of 2 end exponent plus 3 n plus 3 over denominator n end fraction blank f o r blank s o m e blank n element of N close curly brackets comma$ then the number of elements in the set $A comma$ is

If $A equals open curly brackets p element of N colon p blank i s blank a blank p r i m e blank a n d blank p equals fraction numerator 7 n to the power of 2 end exponent plus 3 n plus 3 over denominator n end fraction blank f o r blank s o m e blank n element of N close curly brackets comma$ then the number of elements in the set $A comma$ is

If $A equals open curly brackets 1 comma blank 2 comma blank 3 comma blank 4 close curly brackets comma$ then the number of subsets of $A$ that contain the element 2 but not 3, is

If $A equals open curly brackets 1 comma blank 2 comma blank 3 comma blank 4 close curly brackets comma$ then the number of subsets of $A$ that contain the element 2 but not 3, is

If $A$ and $B$ are two sets such that $n open parentheses A close parentheses equals 7 comma n open parentheses B close parentheses equals 6$ and $open parentheses A intersection B close parentheses not equal to ϕ.$ The least possible value of $n open parentheses A blank capital delta blank B close parentheses comma$ is

If $A$ and $B$ are two sets such that $n open parentheses A close parentheses equals 7 comma n open parentheses B close parentheses equals 6$ and $open parentheses A intersection B close parentheses not equal to ϕ.$ The least possible value of $n open parentheses A blank capital delta blank B close parentheses comma$ is

parallel

If $A equals open curly brackets a comma b comma blank c close curly brackets comma blank B equals left curly bracket b comma blank c comma blank d right curly bracket$ and $C equals left curly bracket a comma blank d comma blank c right curly bracket$ , then $open parentheses A minus B close parentheses cross times left parenthesis B intersection C right parenthesis$ is equal to

If $A equals open curly brackets a comma b comma blank c close curly brackets comma blank B equals left curly bracket b comma blank c comma blank d right curly bracket$ and $C equals left curly bracket a comma blank d comma blank c right curly bracket$ , then $open parentheses A minus B close parentheses cross times left parenthesis B intersection C right parenthesis$ is equal to

Let $A$ and $B$ be two non-empty subsets of a set $X$ such that $A$ is not a subset of $B.$ Then,

Let $A$ and $B$ be two non-empty subsets of a set $X$ such that $A$ is not a subset of $B.$ Then,

If $A$ and $B$ are two sets, then $A minus left parenthesis A minus B right parenthesis$ is equal to

If $A$ and $B$ are two sets, then $A minus left parenthesis A minus B right parenthesis$ is equal to

parallel

In a rehabilitation programme, a group of 50 families were assured new houses and compensation by the government. Number of families who got both is equal to the number of families who got neither of the two. The number of families who got new houses is 6 greater than the number of families who got compensation. How many families got houses?

In a rehabilitation programme, a group of 50 families were assured new houses and compensation by the government. Number of families who got both is equal to the number of families who got neither of the two. The number of families who got new houses is 6 greater than the number of families who got compensation. How many families got houses?

If $A equals open curly brackets x comma y comma z close curly brackets comma$ then the relation
$R equals left curly bracket open parentheses x comma x close parentheses comma open parentheses y comma y close parentheses comma open parentheses z comma z close parentheses comma open parentheses z comma x close parentheses comma left parenthesis z comma y right parenthesis right curly bracket$ is

If $A equals open curly brackets x comma y comma z close curly brackets comma$ then the relation
$R equals left curly bracket open parentheses x comma x close parentheses comma open parentheses y comma y close parentheses comma open parentheses z comma z close parentheses comma open parentheses z comma x close parentheses comma left parenthesis z comma y right parenthesis right curly bracket$ is

In an office, every employee likes at least one of tea, coffee and milk. The number of employees who like only tea, only coffee, only milk and all the three are all equal. The number of employees who like only tea and coffee, only coffee and milk and only tea and milk are equal and each is equal to the number of employees who like all the three. Then a possible value of the number of employees in the office is

In an office, every employee likes at least one of tea, coffee and milk. The number of employees who like only tea, only coffee, only milk and all the three are all equal. The number of employees who like only tea and coffee, only coffee and milk and only tea and milk are equal and each is equal to the number of employees who like all the three. Then a possible value of the number of employees in the office is

parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.