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Easy

Question

If $A equals open curly brackets 1 comma blank 2 comma blank 3 comma blank 4 close curly brackets comma$ then the number of subsets of set $A$ containing element 3, is

24
28
8
16

The correct answer is: 8

Each subset will contain 3 and any number of elements from the remaining 3 elements 1, 2 and 4
So, required number of elements $equals 2 to the power of 2 end exponent equals 8$

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