Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Offsite Campus Turito Championship

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

Maths-

General

Easy

Question

If $a to the power of 4 end exponent blank. b to the power of 5 end exponent equals 1 comma$ then the value of $log subscript a end subscript invisible function application open parentheses a to the power of 5 end exponent b to the power of 4 end exponent close parentheses$ equals

$9 / 5$
$4$
$5$
$8 / 5$

The correct answer is: $9 divided by 5$

Given $4 log subscript a end subscript invisible function application a plus 5 log subscript a end subscript invisible function application b equals 0 rightwards double arrow log subscript a end subscript invisible function application b equals negative 4 divided by 5 blank open parentheses i close parentheses$
Now $log subscript a end subscript invisible function application open parentheses a to the power of 5 end exponent b to the power of 4 end exponent close parentheses equals 5 plus 4 log subscript a end subscript invisible function application b equals 5 plus 4 open parentheses negative fraction numerator 4 over denominator 5 end fraction close parentheses equals 5 minus fraction numerator 16 over denominator 5 end fraction equals fraction numerator 9 over denominator 5 end fraction$

Related Questions to study

If $open parentheses x plus 1 close parentheses to the power of log subscript 10 end subscript invisible function application open parentheses x plus 1 close parentheses end exponent equals 100 open parentheses x plus 1 close parentheses comma$ then

If $open parentheses x plus 1 close parentheses to the power of log subscript 10 end subscript invisible function application open parentheses x plus 1 close parentheses end exponent equals 100 open parentheses x plus 1 close parentheses comma$ then

The sum of all the solution of $cot invisible function application theta equals sin invisible function application 2 theta comma blank open parentheses theta not equal to n pi comma n blank i n t e g e r close parentheses comma blank 0 less or equal than theta less or equal than pi blank$ is

The sum of all the solution of $cot invisible function application theta equals sin invisible function application 2 theta comma blank open parentheses theta not equal to n pi comma n blank i n t e g e r close parentheses comma blank 0 less or equal than theta less or equal than pi blank$ is

The number of solutions of the equation $sin to the power of 3 end exponent invisible function application x cos invisible function application x plus sin to the power of 2 end exponent invisible function application x cos to the power of 2 end exponent invisible function application x plus sin invisible function application x cos to the power of 3 end exponent invisible function application x equals 1 comma blank$ in the interval $open square brackets 0 comma blank 2 pi close square brackets comma blank$ is

The number of solutions of the equation $sin to the power of 3 end exponent invisible function application x cos invisible function application x plus sin to the power of 2 end exponent invisible function application x cos to the power of 2 end exponent invisible function application x plus sin invisible function application x cos to the power of 3 end exponent invisible function application x equals 1 comma blank$ in the interval $open square brackets 0 comma blank 2 pi close square brackets comma blank$ is

parallel

If $a comma blank b blank$ and $blank c$ are the sides of a triangle, then the minimum value of $fraction numerator 2 a over denominator b plus c minus a end fraction plus fraction numerator 2 b over denominator c plus a minus b end fraction plus fraction numerator 2 c over denominator a plus b minus c end fraction$ is

If $a comma blank b blank$ and $blank c$ are the sides of a triangle, then the minimum value of $fraction numerator 2 a over denominator b plus c minus a end fraction plus fraction numerator 2 b over denominator c plus a minus b end fraction plus fraction numerator 2 c over denominator a plus b minus c end fraction$ is

Let $alpha blank a n d blank beta$ be such that $pi less than alpha minus beta less than 3 pi.$ If $sin invisible function application alpha plus sin invisible function application beta equals negative fraction numerator 21 over denominator 65 end fraction blank a n d cos invisible function application alpha plus cos invisible function application beta equals negative fraction numerator 17 over denominator 65 end fraction comma$ then the value of $cos invisible function application fraction numerator alpha minus beta over denominator 2 end fraction$ is

Let $alpha blank a n d blank beta$ be such that $pi less than alpha minus beta less than 3 pi.$ If $sin invisible function application alpha plus sin invisible function application beta equals negative fraction numerator 21 over denominator 65 end fraction blank a n d cos invisible function application alpha plus cos invisible function application beta equals negative fraction numerator 17 over denominator 65 end fraction comma$ then the value of $cos invisible function application fraction numerator alpha minus beta over denominator 2 end fraction$ is

One of the general solutions of $4 sin to the power of 4 end exponent invisible function application x plus cos to the power of 4 end exponent invisible function application x equals 1$ is

One of the general solutions of $4 sin to the power of 4 end exponent invisible function application x plus cos to the power of 4 end exponent invisible function application x equals 1$ is

parallel

Which of the following is not the value of $sin invisible function application 27 degree minus cos invisible function application 27 degree ?$

Which of the following is not the value of $sin invisible function application 27 degree minus cos invisible function application 27 degree ?$

The sum of all roots of $sin invisible function application open parentheses pi log subscript 3 end subscript invisible function application open parentheses fraction numerator 1 over denominator x end fraction close parentheses close parentheses equals 0$ in $blank open parentheses 0 comma blank 2 pi close parentheses$ is

The sum of all roots of $sin invisible function application open parentheses pi log subscript 3 end subscript invisible function application open parentheses fraction numerator 1 over denominator x end fraction close parentheses close parentheses equals 0$ in $blank open parentheses 0 comma blank 2 pi close parentheses$ is

If $sin invisible function application theta subscript 1 end subscript plus sin invisible function application theta subscript 2 end subscript plus sin invisible function application theta subscript 3 end subscript equals 3 comma$ then $cos invisible function application theta subscript 1 end subscript plus cos invisible function application theta subscript 2 end subscript plus cos invisible function application theta subscript 3 end subscript$ is equal to

If $sin invisible function application theta subscript 1 end subscript plus sin invisible function application theta subscript 2 end subscript plus sin invisible function application theta subscript 3 end subscript equals 3 comma$ then $cos invisible function application theta subscript 1 end subscript plus cos invisible function application theta subscript 2 end subscript plus cos invisible function application theta subscript 3 end subscript$ is equal to

parallel

The set of values of $theta$ satisfying the inequation $2 sin to the power of 2 end exponent invisible function application theta minus 5 sin invisible function application theta plus 2 greater than 0$ , where $0 less than theta less than 2 pi$ , is

The set of values of $theta$ satisfying the inequation $2 sin to the power of 2 end exponent invisible function application theta minus 5 sin invisible function application theta plus 2 greater than 0$ , where $0 less than theta less than 2 pi$ , is

In any triangle $A B C comma fraction numerator a to the power of 2 end exponent plus b to the power of 2 end exponent plus c to the power of 2 end exponent over denominator R to the power of 2 end exponent end fraction$ has the maximum value of

In any triangle $A B C comma fraction numerator a to the power of 2 end exponent plus b to the power of 2 end exponent plus c to the power of 2 end exponent over denominator R to the power of 2 end exponent end fraction$ has the maximum value of

In triangle $A B C comma blank a equals 5 comma blank b equals 4 blank$ and $blank c equals 3. blank G$ is the centroid of the triangle. Circumradius of triangle $G A B$ is equal to

In triangle $A B C comma blank a equals 5 comma blank b equals 4 blank$ and $blank c equals 3. blank G$ is the centroid of the triangle. Circumradius of triangle $G A B$ is equal to

parallel

We are given $b comma blank c blank$ and $sin invisible function application B$ such that $B$ is acute and $b less than c sin invisible function application B.$ Then

We are given $b comma blank c blank$ and $sin invisible function application B$ such that $B$ is acute and $b less than c sin invisible function application B.$ Then

Number of ordered pair $open parentheses s close parentheses open parentheses a comma blank b close parentheses$ for each of which the equality $a open parentheses cos invisible function application x minus 1 close parentheses plus b to the power of 2 end exponent equals cos invisible function application open parentheses a x plus b to the power of 2 end exponent close parentheses minus 1$ holds true for all $x element of R$ are

Number of ordered pair $open parentheses s close parentheses open parentheses a comma blank b close parentheses$ for each of which the equality $a open parentheses cos invisible function application x minus 1 close parentheses plus b to the power of 2 end exponent equals cos invisible function application open parentheses a x plus b to the power of 2 end exponent close parentheses minus 1$ holds true for all $x element of R$ are

$I f tan invisible function application x equals b divided by a comma blank t h e n blank square root of open parentheses a plus b close parentheses divided by open parentheses a minus b close parentheses end root plus square root of open parentheses a minus b close parentheses divided by open parentheses a plus b close parentheses end root$ is equal to

$I f tan invisible function application x equals b divided by a comma blank t h e n blank square root of open parentheses a plus b close parentheses divided by open parentheses a minus b close parentheses end root plus square root of open parentheses a minus b close parentheses divided by open parentheses a plus b close parentheses end root$ is equal to

parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.