Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Offsite Campus Turito Championship

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

Maths-

General

Easy

Question

$text If a end text equals cos squared invisible function application straight A plus ysin squared space straight A space then space left parenthesis straight x minus straight a right parenthesis left parenthesis straight y minus straight a right parenthesis plus left parenthesis straight x minus straight y right parenthesis squared sin squared space Acos squared space straight A equals$

0
1
$x y + a^{2}$
$x y - a^{2}$

The correct answer is: 0

$T a n g e n t blank o f blank open parentheses x subscript 1 end subscript comma y subscript 1 end subscript close parentheses blank i s blank x x subscript 1 end subscript plus y y subscript 1 end subscript minus a to the power of 2 end exponent equals 0$
$A blank open parentheses fraction numerator a to the power of 2 end exponent over denominator x subscript 1 end subscript end fraction comma 0 close parentheses comma blank B open parentheses 0 comma fraction numerator a to the power of 2 end exponent over denominator y subscript 1 end subscript end fraction blank close parentheses$
$M i d p o i n t blank o f blank stack A B with minus on top equals$ $open parentheses fraction numerator a to the power of 2 end exponent over denominator 2 x subscript 1 end subscript end fraction comma fraction numerator a to the power of 2 end exponent over denominator 2 y subscript 1 end subscript end fraction close parentheses blank l i e s blank o n blank x to the power of 2 end exponent plus y to the power of 2 end exponent equals a to the power of 2 end exponent$
$open parentheses fraction numerator a to the power of 2 end exponent over denominator 2 x subscript 1 end subscript end fraction close parentheses to the power of 2 end exponent plus open parentheses fraction numerator a to the power of 2 end exponent over denominator 2 y subscript 1 end subscript end fraction close parentheses to the power of 2 end exponent equals a to the power of 2 end exponent$
$L o c u s blank o f blank p blank i s blank a to the power of 2 end exponent open parentheses x to the power of 2 end exponent plus y to the power of 2 end exponent close parentheses equals 4 x to the power of 2 end exponent y to the power of 2 end exponent$

Related Questions to study

$text If end text fraction numerator cos squared begin display style text end text end style theta over denominator a end fraction equals fraction numerator sin squared begin display style space end style theta over denominator b end fraction text then end text fraction numerator cos to the power of 4 begin display style text end text end style theta over denominator a end fraction plus fraction numerator sin to the power of 4 begin display style space end style theta over denominator b end fraction equals$

$text If end text fraction numerator cos squared begin display style text end text end style theta over denominator a end fraction equals fraction numerator sin squared begin display style space end style theta over denominator b end fraction text then end text fraction numerator cos to the power of 4 begin display style text end text end style theta over denominator a end fraction plus fraction numerator sin to the power of 4 begin display style space end style theta over denominator b end fraction equals$

$tan space A equals a tan space B comma sin space A equals b sin space B not stretchy rightwards arrow fraction numerator a to the power of negative 1 end exponent 1 over denominator a squared equals 1 end fraction equals$

$tan space A equals a tan space B comma sin space A equals b sin space B not stretchy rightwards arrow fraction numerator a to the power of negative 1 end exponent 1 over denominator a squared equals 1 end fraction equals$

$text a sec end text theta plus b tan space theta equals 1 comma text a sec end text theta minus b tan space theta equals 5 not stretchy rightwards double arrow a squared open parentheses b squared plus 4 close parentheses equals$

$text a sec end text theta plus b tan space theta equals 1 comma text a sec end text theta minus b tan space theta equals 5 not stretchy rightwards double arrow a squared open parentheses b squared plus 4 close parentheses equals$

parallel

if $x equals acos squared space theta sin space theta$ and $y equals asin squared space theta cos space theta$ then $fraction numerator open parentheses x squared plus y squared close parentheses to the power of 4 over denominator x squared y squared end fraction equals$

if $x equals acos squared space theta sin space theta$ and $y equals asin squared space theta cos space theta$ then $fraction numerator open parentheses x squared plus y squared close parentheses to the power of 4 over denominator x squared y squared end fraction equals$

$cos squared space 5 to the power of ring operator plus cos squared space 10 to the power of minus plus cos squared space 15 to the power of ring operator plus midline horizontal ellipsis plus cos squared space 360 to the power of ring operator equals$

$cos squared space 5 to the power of ring operator plus cos squared space 10 to the power of minus plus cos squared space 15 to the power of ring operator plus midline horizontal ellipsis plus cos squared space 360 to the power of ring operator equals$

If $1 plus sin space x plus sin squared space x plus$ to $straight infinity equals 4 plus 2 square root of 3 comma 0 less than x less than pi$ and $x not equal to 11 over 2 text then end text x equals$

If $1 plus sin space x plus sin squared space x plus$ to $straight infinity equals 4 plus 2 square root of 3 comma 0 less than x less than pi$ and $x not equal to 11 over 2 text then end text x equals$

parallel

If sin $theta plus$ cos $theta equals$ m and sec $theta plus$ cosec $theta equals$ n, then $n left parenthesis m plus 1 right parenthesis left parenthesis m minus 1 right parenthesis equals$

If sin $theta plus$ cos $theta equals$ m and sec $theta plus$ cosec $theta equals$ n, then $n left parenthesis m plus 1 right parenthesis left parenthesis m minus 1 right parenthesis equals$

if $square root of fraction numerator 1 minus sin space A over denominator 1 plus sin space A end fraction end root equals$ sec A-tan A then lies in the quadrants

if $square root of fraction numerator 1 minus sin space A over denominator 1 plus sin space A end fraction end root equals$ sec A-tan A then lies in the quadrants

cosec $straight A equals 4 straight p plus fraction numerator 1 over denominator 16 straight p end fraction not stretchy rightwards double arrow$ cosec A +cot A=

cosec $straight A equals 4 straight p plus fraction numerator 1 over denominator 16 straight p end fraction not stretchy rightwards double arrow$ cosec A +cot A=

parallel

The total amount of fee collection for 21 students is $31500. How much was paid by each student.

The total amount of fee collection for 21 students is $31500. How much was paid by each student.

is a

is a

Chemistry-General

In the reaction,

In the reaction,

Chemistry-General

parallel

In the given action,

the product [X] will be:

In the given action,

the product [X] will be:

Chemistry-General

In the reaction sequence,

In the reaction sequence,

Chemistry-General

In the given reaction,

In the given reaction,

Chemistry-General

parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.