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If capital delta(x) = open vertical bar table row cell e to the power of x end cell cell s i n invisible function application 2 x end cell cell t a n invisible function application x squared end cell row cell invisible function application left parenthesis 1 plus x right parenthesis end cell cell c o s invisible function application x end cell cell s i n invisible function application x end cell row cell c o s invisible function application x squared end cell cell e to the power of x minus 1 end cell cell s i n invisible function application x squared end cell end table close vertical bar= A + Bx + Cx2, then B is equal to

  1. 0    
  2. 1    
  3. 2    
  4. None of these    

The correct answer is: 0


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